All categories

3 years ago

What is the function of the endoplasmic reticulum?

Chemistry

1 answer:

Semenov [28]3 years ago

8 0

Answer:

option d

Explanation:

it is a passage for the nucleus and the rest of the cell

You might be interested in

What would be the mass of a 33.5dm3 sample of O2 at STP?

liraira [26]

Answer:

• One mole of oxygen is equivalent to 16 grams.

→ But at STP, 22.4 dm³ are occupied by 1 mole.

${ \tt{22.4 \: {dm}^{3} \: \dashrightarrow \: 16 \: grams}} \\ { \tt{33.5 \: {dm}^{3} \: \dashrightarrow \: ( \frac{33.5 \times 16}{22.4} ) \: grams}} \\ \\ \dashrightarrow \: { \boxed{ \tt{23.94 \: g \approx \: 24 \: grams}}}$

7 0

3 years ago

A sample of metal has a mass of 5. 2 g and absorbs 20. 0 j of energy as it is heated from 30. 0°c to 40. 0°c. What is the identi

kiruha [24]

The identity of the metal is copper.

<h3>What is specific heat?</h3>

The amount of energy needed to raise the temperature of one gram of a substance by one degree Celsius.

Using the formula of specific heat

H = mcdT

Where, H = Heat absorbed

m = mass of the metal

c = specific heat capacity of the metal

dT = temperature change

Putting the values in the equation

20 J = 0.0052 Kg × c × ( 40.0°C - 30.0°C)

c = 20 J/0.0052 Kg × ( 40.0°C - 30.0°C)

c = 385 JKg-1°C-1

Thus, the metal is copper.

Learn more about specific heat

brainly.com/question/11297584

#SPJ4

6 0

2 years ago

Why was there so much disagreements among the ancient greeks about the nature of the atoms?

olga2289 [7]

It is because in that time science was not established. This is, the experimentation to test hypotheses, which is a fundamental part of the scientific method, was not applied.

Atoms can not be seen, then they could only reflect or philosophize on this matter. This method is not able to give good answers to so complicated scientific matters.

4 0

3 years ago

A balance reads an object A to be 45.1 kg. The balance reads another object B to be 33.46 kg. What is the total weight of both o

postnew [5]

Answer:

The total weight of both object is 78.56 kg.

Explanation:

Given data:

Mass of object A = 45.1 kg

Mass of object B = 33.46 kg

Total weight of object = ?

Solution:

Total weight of both subject must be the sum of weight of object A and B.

Total weight of objects = weight of object A + weight of object B

Now we will put the values of mass of object A and B.

Total weight of objects = 45.1 kg + 33.46 kg

Total weight of objects =78.56 kg

Thus the total weight of both object is 78.56 kg.

7 0

3 years ago

Glucose (C6H12O6) can be fermented to yield ethanol (CH3CH2OH) and carbon dioxide (CO2). C6H12O6⟶2CH3CH2OH+2CO2 The molar mass o

jekas [21]

Answer:

The % yield is 74.45 %

Explanation:

Step 1: The balanced equation

C6H12O6⟶2CH3CH2OH+2CO2

Step 2: Data given

Molar mass glucose = 180.15 g/mol

Molar mass of ethanol = 46.08 g/mol

Molar mass of carbon dioxide = 44.01 g/mol

Mass of glucose = 61.5 grams

Mass of ethanol = 23.4 grams

Step 3: Calculate moles of glucose

Moles glucose = Mass glucose / Molar mass of glucose

Moles glucose = 61.5 grams / 180.15 g/mol

Moles glucose = 0.341 moles

Step 4: Calculate moles of ethanol

1 mole of glucose consumed, produces 2 moles of ethanol and 2 moles of CO2

0.341 moles of glucose, will produce 2*0.341 = 0.682 moles of ethanol

Step 5: Calculate mass of ethanol

Mass ethanol = moles ethanol * Molar mass ethanol

Mass ethanol = 0.682 moles * 46.08 g/mol

Mass ethanol = 31.43 grams = theoretical mass

Step 6: Calculate % yield

% yield = actual mass / theoretical mass

% yield = (23.4 grams / 31.43 grams) * 100%

% yield = 74.45 %

The % yield is 74.45 %

7 0

3 years ago