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REY [17]
3 years ago
9

Write hypothesis about a valcano

Chemistry
1 answer:
Afina-wow [57]3 years ago
6 0

Answer:

My hypothesis of a volcano is that it'll explode when it reaches it's maximum temperature

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The most common form of energy encountered in chemical reactions is _____. Select one:
Svetllana [295]
The answer is b heat
3 0
3 years ago
What is the purpose of graphics in scientific articles
kow [346]

Answer:

Graphics can sometimes convey more information in a brief amount of space than an author can explain in a paragraph.

4 0
3 years ago
10.0 g Cu, C Cu = 0.385 J/g°C 10.0 g Al, C Al = 0.903 J/g°C 10.0 g ethanol, Methanol = 2.42 J/g°C 10.0 g H2O, CH2O = 4.18 J/g°C
Mazyrski [523]

Answer:

Lead shows the greatest temperature change upon absorbing 100.0 J of heat.

Explanation:

Q=mc\Delte T

Q = Energy gained or lost by the substance

m = mass of the substance

c = specific heat of the substance

ΔT = change in temperature

1) 10.0 g of copper

Q = 100.0 J (positive means that heat is gained)

m = 10.0 g

Specific heat of the copper = c =  0.385 J/g°C

\Delta T=\frac{Q}{mc}

=\frac{100.0 J}{10 g\times 0.385J/g^oC}=25.97^oC

2) 10.0 g of aluminium

Q = 100.0 J (positive means that heat is gained)

m = 10.0 g

Specific heat of the aluminium= c =  0.903 J/g°C

\Delta T=\frac{Q}{mc}

=\frac{100.0 J}{10 g\times 0.903 J/g^oC}=11.07^oC

3) 10.0 g of ethanol

Q = 100.0 J (positive means that heat is gained)

m = 10.0 g

Specific heat of the ethanol= c =  2.42 J/g°C

\Delta T=\frac{Q}{mc}

=\frac{100.0 J}{10 g\times 2.42 J/g^oC}=4.13 ^oC

4) 10.0 g of water

Q = 100.0 J (positive means that heat is gained)

m = 10.0 g

Specific heat of the water = c =  4.18J/g°C

\Delta T=\frac{Q}{mc}

=\frac{100.0 J}{10 g\times 4.18 J/g^oC}=2.39 ^oC

5) 10.0 g of lead

Q = 100.0 J (positive means that heat is gained)

m = 10.0 g

Specific heat of the lead= c =  0.128 J/g°C

\Delta T=\frac{Q}{mc}

=\frac{100.0 J}{10 g\times 0.128 J/g^oC}=78.125^oC

Lead shows the greatest temperature change upon absorbing 100.0 J of heat.

3 0
4 years ago
How many oxygen atoms are present in 3 grams of glucose
Kaylis [27]

Answer:

Because CLEARLY, each mole of glucose, C6H12O6 contains 6⋅mol oxygen atoms.

5 0
3 years ago
Given below is the balanced equation for the combustion of decane. 2C10H22 (l) + 31O2 (g) --> 20CO2 (g) + 22H2O (g) What is t
Aleks [24]

Answer: The ratio of carbon dioxide molecules to oxygen molecules is 20 :31

Explanation:

Combustion is a chemical reaction in which hydrocarbons are burnt in the presence of oxygen to give carbon dioxide and water.

According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side. Thus chemical equations are balanced.

The balanced combustion reaction is,:

2C_{10}H_{22}(l)+31O_2(g)\rightarrow 20CO_2(g)+22H_2O(g)

Thus the ratio of carbon dioxide molecules to oxygen molecules is 20 : 31

3 0
3 years ago
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