The area of the polygon with the given vertices is of 7.5 square units.
<h3>What is the area of a right triangle?</h3>
The area of a right triangle is given by half the multiplication of the lengths of it's sides.
The polygon in this problem is a right triangle with sides 3 and 5, hence the area is given by:
A = 0.5 x 3 x 5 = 7.5 square units.
More can be learned about the area of a right triangle at brainly.com/question/17335144
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Answer:
The Proof with Figure, Statement and Reasons is given below.
Step-by-step explanation:
Given:
∠DAF ≅ ∠EBF,
DF ≅ FE
Prove:
Δ ADF ≅ Δ BFE
Proof:
Statements Reasons
a. ∠DAF ≅ ∠EBF ...........................Given
<u>48. ∠DFA ≅ ∠EFB </u>..........................Vertical Angles are congruent
DF ≅ FE ..........................<u>.49. Given</u>
50.<u> Δ ADF ≅ Δ BFE </u>.......................<u>..By Angle-Angle-Side test</u>
Answer:
4
Step-by-step explanation:
Answer:
ok
Step-by-step explanation:
Answer:
4x^2 -25
Step-by-step explanation:
The other factor of the difference of squares is the "conjugate" of the given one: (2x -5). Then their product is ...
(2x +5)(2x -5) = (2x)^2 -(5)^2 = 4x^2 -25