Chlorine can be prepared in the laboratory by the reaction of manganese dioxide with hydrochloric acid, HCl (aq), as described b
y the chemical equation
MnO₂ (s) + 4HCl (aq) ⟶ MnCl₂ (aq) + 2H₂O (l) + Cl₂ (g)
How much MnO₂ (s) should be added to excess HCl (aq) to obtain 115 mL Cl₂ (g) at 25 °C and 805 Torr?
MnO₂ (s) + 4HCl (aq) ⟶ MnCl₂ (aq) + 2H₂O (l) + Cl₂ (g)
How much MnO₂ (s) should be added to excess HCl (aq) to obtain 115 mL Cl₂ (g) at 25 °C and 805 Torr?
1 answer:
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Answer: A 0.20 M solution of HCl with a volume of 15.0 mL is exactly neutralized by the 0.10 M solution of NaOH with 3 mL volume.
Explanation:
Given: = 0.20 M,
= 15.0 mL
= 0.10 M,
= ?
Formula used is as follows.
Substitute the values into above formula s follows.
Thus, we can conclude that a 0.20 M solution of HCl with a volume of 15.0 mL is exactly neutralized by the 0.10 M solution of NaOH with 3 mL volume.