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Juliette [100K]
3 years ago
13

Chlorine can be prepared in the laboratory by the reaction of manganese dioxide with hydrochloric acid, HCl (aq), as described b

y the chemical equation
MnO₂ (s) + 4HCl (aq) ⟶ MnCl₂ (aq) + 2H₂O (l) + Cl₂ (g)
How much MnO₂ (s) should be added to excess HCl (aq) to obtain 115 mL Cl₂ (g) at 25 °C and 805 Torr?

Chemistry
1 answer:
Anestetic [448]3 years ago
6 0

Answer:

0.433 gram

Explanation:

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If you were asked to convert 4.2 × 1022 atoms of aluminum to moles, which of the following should you use for the conversion?
DanielleElmas [232]
<span><span>4.2×1022</span>NA</span><span> N_{A} is the avagadro number</span>
7 0
3 years ago
One isotope of Br has a half-life of 16.5 hours. How much of a 2.00 gram sample remains at the end of 1.00 day?
valina [46]

Answer:

half life=16.5hrs

sample=2g

total time=1day=24hrs

no. of half lives=total time/half life

no. of half lives=24hrs/16.5hrs=1.45approx1.5

sample left=1/2n=1/2[1.5]=0.707gapprox

Explanation:

4 0
3 years ago
If 3.00 mL of 0.0250 M CuSO4 is diluted to 25.0 mL with pure water, what is the molarity of copper(II) sulfate in the diluted so
g100num [7]

Answer:

0.00268 M

Explanation:

To find the new molarity, you need to (1) find the moles of CuSO₄ (via the molarity equation using the beginning molarity and volume) and then (2) find the new molarity (using the moles and combined volume). Your final answer should have 3 sig figs to match the given values.

<u>Step 1:</u>

3.00 mL / 1,000 = 0.00300 L

Molarity = moles / volume (L)

0.0250 M = moles / 0.00300 L

(0.0250 M) x (0.00300 L) = moles

7.50 x 10⁻⁵ = moles

<u>Step 2:</u>

25.0 mL / 1,000 = 0.0250 L

0.0250 L + 0.00300 L = 0.0280 L

Molarity = moles / volume (L)

Molarity = (7.50 x 10⁻⁵ moles) / (0.0280 L)

Molarity = 0.00268 M

8 0
1 year ago
You may expect _____
TiliK225 [7]

Answer:

covalent..............

5 0
2 years ago
How many atoms are in 8.28 moles of aluminum?
Lilit [14]

Answer:

49.86 × 10²³  atoms of Al

Explanation:

Given data:

Number of moles of Al = 8.28 mol

Number of atoms = ?

Solution:

The given problem will solve by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.

The number 6.022 × 10²³ is called Avogadro number.

For example,

18 g of water = 1 mole = 6.022 × 10²³ molecules of water

1.008 g of hydrogen = 1 mole = 6.022 × 10²³ atoms of hydrogen

For 8.28 moles of Al:

1 mole = 6.022 × 10²³  atoms of Al

8.28 mol×6.022 × 10²³  atoms / 1mol

49.86 × 10²³  atoms of Al

4 0
3 years ago
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