Chlorine can be prepared in the laboratory by the reaction of manganese dioxide with hydrochloric acid, HCl (aq), as described b
y the chemical equation
MnO₂ (s) + 4HCl (aq) ⟶ MnCl₂ (aq) + 2H₂O (l) + Cl₂ (g)
How much MnO₂ (s) should be added to excess HCl (aq) to obtain 115 mL Cl₂ (g) at 25 °C and 805 Torr?
MnO₂ (s) + 4HCl (aq) ⟶ MnCl₂ (aq) + 2H₂O (l) + Cl₂ (g)
How much MnO₂ (s) should be added to excess HCl (aq) to obtain 115 mL Cl₂ (g) at 25 °C and 805 Torr?
1 answer:
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Answer: There are atoms of hydrogen are present in 40g of urea,
.
Explanation:
Given: Mass of urea = 40 g
Number of moles is the mass of substance divided by its molar mass.
First, moles of urea (molar mass = 60 g/mol) are calculated as follows.
According to the mole concept, 1 mole of every substance contains atoms.
So, the number of atoms present in 0.67 moles are as follows.
In a molecule of urea there are 4 hydrogen atoms. Hence, number of hydrogen atoms present in 40 g of urea is as follows.
Thus, we can conclude that there are atoms of hydrogen are present in 40g of urea,
.