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frozen [14]
3 years ago
7

What are Norton's formulas?​

Physics
1 answer:
Sladkaya [172]3 years ago
6 0

Answer:saasd

Explanation:ssas

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If the frequency of a FM wave is 8.85 × 107 hertz, what is the period of the FM wave?
patriot [66]

Answer:

1.1299 x 10^-8   second    

Explanation:

Period = 1 / f = 1 / (8.85 * 10^7) = 1.1299 x 01^-8  sec

8 0
2 years ago
Carbon has six protons. which model shows a neutral atom of carbon?
Likurg_2 [28]

Answer:

Hi myself Shrushtee

Explanation:

Neutral carbon-12 (or any carbon atom) has 6 electrons with a total negative charge of 6e- orbiting a nucleus with a total positive charge of 6e+, so that the total net charge is zero. The nucleus is made up of 6 protons, each with a positive charge of e+, and 6 neutrons, each with zero charge.

please mark me as brainleist

7 0
3 years ago
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In the diagram, q1 = +6.39*10^_9 C and
ivanzaharov [21]

Answer:

The electric potential will be "259.695 volt".

Explanation:

In the given question, the figure is not provided. Below is the attached figure given.

Given:

q_1=6.39\times 10^{-9} \ C

q_2=3.22\times 10^{-9} \ C

AP=(0.150+0.250)

      =0.40 \ m

BP=0.25 \ m

Now,

At point P, the electric potential will be:

⇒ V=\frac{q_1}{4 \pi \epsilon_o AP } +\frac{q_2}{4 \pi \epsilon_o BP}

By putting values, we get

⇒     =9\times 10^9 [\frac{6.39\times 10^{-9}}{0.40} +\frac{3.22\times 10^{-9}}{0.25} ]

⇒     =259.695 \ Volt

4 0
3 years ago
Explain a situation in which you can accelerate even thought your speed doesn’t change
Juli2301 [7.4K]

Explanation:

An object's acceleration is the rate its velocity (speed and direction) changes. Therefore, an object can accelerate even if its speed is constant - if its direction changes. ... Light's acceleration is zero. Since it travels in a straight line, its direction does not change.

7 0
3 years ago
Which of the following is considered to be a vector? 
AVprozaik [17]

Answer: B) Velocity

Explanation:

Velocity is a vector quantity. Velocities have both magnitude and direction.

8 0
3 years ago
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