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AleksandrR [38]
3 years ago
15

Is a charge indicated on the neutral atoms if yes where is it located?

Physics
1 answer:
Nesterboy [21]3 years ago
8 0
<span>There are charges in a neutral atom. These charges belong to electron and proton which is balanced inside the neutral atom. But basically, neutral atoms do not have any charges because since the number of protons (positively charged electron), and the number of neutrons (negatively charged electrons or no charged at all) are balanced making the charge equals to zero. </span>
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What type of medium (solids, liquids, or gases) do sound waves travel fastest in?
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Answer:

Gases

Explanation:

Gases molecules are farther apart than solids and liquids. :)

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A 35 kg boy is riding a 65 kg go-cart. He pushes on the gas pedal, causing the cart to accelerate at 5 m/s2. Use the equation F
trasher [3.6K]

Answer:

\boxed {\boxed {\sf 500 \ Newtons }}

Explanation:

The equation for force is given:

F=m*a

First, we must find the total mass, which is the sum of the boy's mass and the go-cart's mass.

  • total mass= boy's mass + go cart's mass

The boy's mass is 35 kilograms and the go cart's is 65 kilograms.

  • total mass= 35 kg+ 65 kg=100 kg

Now we know the total mass and the acceleration.

m= 100 \ kg \\a= 5 \ m/s^2

Substitute the values into the formula.

F=100 \ kg * 5 \ m/s^2

Multiply.

F= 500 \ kg*m/s^2

  • 1 kilograms meter per square second is equal to 1 Newton.
  • Our answer of 500 kg*m/s² is equal to 500 Newtons.

F= 500 \ N

The force exerted by the go cart engine is <u>500 Newtons.</u>

4 0
2 years ago
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A rocket accelerates by burning its onboard fuel, so its mass decreases with time. Suppose the initial mass of the rocket at lif
Serggg [28]

Answer:

Height of the rocket be one minute after liftoff is 40.1382 km.

Explanation:

v(t)=-gt-v_e\times \ln \frac{m-rt}{m}

v = velocity of rocket at time t

g = Acceleration due to gravity =9.8 m/s^2

v_e = Constant velocity relative to the rocket = 2,900m/s.

m = Initial mass of the rocket at liftoff = 29000 kg

r = Rate at which fuel is consumed = 170 kg/s

Velocity of the rocket after 1 minute of the liftoff =v

t = 1 minute = 60 seconds'

Substituting all the given values in in the given equation:

v(60)=-9.8 m/s^2\times 60 s-2,900m/s\times \ln (\frac{29,000 kg-170 kg/s\times 60 s}{2,9000 kg})

v(60) = 668.97 m/s

Height of the rocket = h

Velocity=\frac{Displacement}{time}

668.97 m/s=\frac{h}{60 s}

h=668.97 m/s\times 60 s=40,138.2 m = 40.1382 km

Height of the rocket be one minute after liftoff is 40.1382 km.

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