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3 years ago

What are three subatomic particles

Chemistry

2 answers:

Alinara [238K]3 years ago

6 0

Protons, neutrons, and electrons

alekssr [168]3 years ago

5 0

Protons, Neutrons And Electrons

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Pleaseeeeee help me i will mark you brailiesttttttttttttttttttttttttttttttttttttttt

Alekssandra [29.7K]

Answer:

A.), as it will decrease.

8 0

3 years ago

At STP how many moles or helium would occupy a volume of 12 liters?

butalik [34]

1 mole ------------- 22.4 L ( at STP )
?? mole ---------- 12 L

12 x 1 / 22.4 => 0.5357 moles

hope this helps!

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4 years ago

Why do you think learning about how atomic theory has evolved is important?

Yanka [14]

I feel like it is important, because it is always nice to learn about new things and keep your mind open, to expand your knowledge.

I hope this helps ^-^

7 0

3 years ago

What change in volume results if 170.0 mL of gas is cooled from 30.0 °C to 20.0 °C? (CHARLES LAW)

Inessa05 [86]

Answer:

164.4 L

Explanation:

use charles' law formula Volume 1 over Temp. 1 equaled to Volume 2 over Temp. 2

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3 years ago

A food processing plant discharges 40 cfs (cubic feet per second) of process water containing an ultimate BOD (L0) of 25 mg/L an

Feliz [49]

Answer:

The right solution according to the question is provided below.

Explanation:

According to the question,

(a)

The initial conditions will be:

DO = $\frac{(40\times 1.8)+(260\times 7.6)}{40+260}$

= $\frac{2048}{300}$

= $6.826 \ mg/L$

The initial oxygen defict will be:

Do = $8.5-6.826$

= $1.674 \ mg/L$

The initial BOD will be:

Lo = $\frac{(40\times 25)+(260\times 3.6)}{40+260}$

= $\frac{1936}{300}$

= $6.453 \ mg/L$

(b)

The time reach minimum DO:

tc = $\frac{1}{(kr-kd)} ln{(\frac{0.76}{0.61} )[1-\frac{1.674(0.76-0.61)}{0.61\times 6.453} ]}$

= $\frac{1}{0.15}\times ln \ 1.158$

By putting the values of log, we get

= $0.973 \ days$

The distance to reach minimum DO will be:

Xc = $\frac{1.1\times 3600\times 24}{5280}\times 0.973 \ days$

= $18\times 0.973$

= $17.5 \ miles$

8 0

3 years ago