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2 years ago

If an element has 12 protons and 17 neutrons, how many electrons must it have?

Chemistry

2 answers:

kati45 [8]2 years ago

8 0

Number of electrons = Number of Protons

So, Number of electrons will be 12

ad-work [718]2 years ago

3 0

The elements are electrically neutral, this is they have the same amount of positive as negative charge.

Electrons and protons have each the same amount of charge but different sign. Eletrons are negative and protons are positive.

Then to be neutral, the number of electrons must be equal to the number of protons. This mean that the element must have 12 electrons.

Answer: 12.

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Ca + ZnCO3 → CaCO3 + Zn

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2 years ago

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What is the pH of a 0.0042 M hydrochloric acid solution?

babymother [125]

Answer:

E) 2.38

Explanation:

The pH of any solution , helps to determine the acidic strength of the solution ,

i.e. ,

Lower the value of pH , higher is its acidic strength

and ,

Higher the value of pH , lower is its acidic strength .

pH is given as the negative log of the concentration of H⁺ ions ,

hence ,

pH = - log H⁺

From the question ,

the concentration of the solution is 0.0042 M , and being it a strong acid , dissociates completely to its respective ions ,

Therefore , the concentration of H⁺ = 0.0042 M .

Hence , using the above equation , the value of pH can be calculated as follows -

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pH = 2.38 .

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3 years ago

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3 years ago

Use the equation editor or "Insert Chemistry - WIRIS editor" to write the balanced molecular chemical equation for the reaction

11Alexandr11 [23.1K]

Answer:

<u>Balanced equation:</u>

$Pb(NO_{3})_{2}(aq)+K_{2}CO_{3}(aq)\rightarrow PbCO_{3}(s)+2KNO_{3}(aq)$

Explanation:

The chemical reaction between Lead(II) Nitrate and potassium carbonate is as follows.

$Lead(II)Nitrate+Potassium\,carbonate \rightarrow Lead(III)\,\,carbonate+Potassium\,nitrate$

$Pb(NO_{3})_{2}(aq)+K_{2}CO_{3}(aq)\rightarrow PbCO_{3}(s)+2KNO_{3}(aq)$

<u>Ionic equation:</u>

$Pb^{2+}(aq)+2NO_{3}^{-}(aq)+2K^{+}(aq)+CO_{3}^{2-}(aq)\Leftrightarrow PbCO_{3}(s)+K^{+}(aq)+2NO_{3}^{-}$

Cancel the same ions on the both sides of the reaction.

The net ionic equation is as follows.

$Pb^{2+}(aq)+CO_{3}^{2-}(aq)\Leftrightarrow PbCO_{3}(s)$

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Explanation:

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