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Inessa [10]
3 years ago
11

Sodium sulfate reacts with carbon to produce the products sodium sulfide and carbon monoxide. Identify the reducing agent in the

following reaction.
Na2SO4 + 4C yields Na2S + 4CO

Na2SO4
C
Na2S
CO
Chemistry
2 answers:
Lunna [17]3 years ago
7 0

Answer : The correct option is, carbon (C)

Explanation :

Oxidizing agent : Oxidizing agent are the agent that gains electrons and is reduced in a chemical reaction.

Reducing agent : Reducing agent are the agent that lose electrons and is oxidized in a chemical reaction.

The given balanced chemical reaction is,

Na_2SO_4+4C\rightarrow Na_2S+4CO

First we have to calculate the oxidation number of sulfur and carbon.

The oxidation state of 'S' in Na_2SO_4 and Na_2S are, (+6) and (-2) respectively.

The oxidation state of 'C' in 4C and 4CO are, (0) and (+2) respectively.

From this we conclude that, the Na_2SO_4 act as an oxidizing agent and 'C' act as a reducing agent.

Hence, the reducing agent in the following reaction is, carbon (C)

Maslowich3 years ago
6 0
The reducing agent will itself be oxidized.
The oxidation number of carbon goes form 0 to +2. Therefore, it is the reducing agent.
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