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Inessa [10]
3 years ago
11

Sodium sulfate reacts with carbon to produce the products sodium sulfide and carbon monoxide. Identify the reducing agent in the

following reaction.
Na2SO4 + 4C yields Na2S + 4CO

Na2SO4
C
Na2S
CO
Chemistry
2 answers:
Lunna [17]3 years ago
7 0

Answer : The correct option is, carbon (C)

Explanation :

Oxidizing agent : Oxidizing agent are the agent that gains electrons and is reduced in a chemical reaction.

Reducing agent : Reducing agent are the agent that lose electrons and is oxidized in a chemical reaction.

The given balanced chemical reaction is,

Na_2SO_4+4C\rightarrow Na_2S+4CO

First we have to calculate the oxidation number of sulfur and carbon.

The oxidation state of 'S' in Na_2SO_4 and Na_2S are, (+6) and (-2) respectively.

The oxidation state of 'C' in 4C and 4CO are, (0) and (+2) respectively.

From this we conclude that, the Na_2SO_4 act as an oxidizing agent and 'C' act as a reducing agent.

Hence, the reducing agent in the following reaction is, carbon (C)

Maslowich3 years ago
6 0
The reducing agent will itself be oxidized.
The oxidation number of carbon goes form 0 to +2. Therefore, it is the reducing agent.
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hammer [34]

Answer:

Covalent bond is a type of bond involves the bonding of two ions of opposite charges.

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7 0
2 years ago
Use calc to determine whether it is possible to remove 99.99% Cu2 by converting it to Cu(s) in a solution mixture containing 0.1
inessss [21]

Answer:

it is possible to remove 99.99% Cu2 by converting it to Cu(s)

Explanation:

So, from the question/problem above we are given the following ionic or REDOX equations of reactions;

Cu2+ + 2e- <--------------------------------------------------------------> Cu (s) Eo= 0.339 V

Sn2+ + 2e- <---------------------------------------------------------------> Sn (s) Eo= -0.141 V

In order to convert 99.99% Cu2 into Cu(s), the equation of reaction given below is needed:

Cu²⁺ + Sn ----------------------------------------------------------------------------> Cu + Sn²⁺.

Therefore, E°[overall] = 0.339 - [-0.141] = 0.48 V.

Therefore, the change in Gibbs' free energy, ΔG° = - nFE°. Where E° = O.48V, n= 2 and F = 96500 C.

Thus, ΔG° = - 92640.

This is less than zero[0]. Therefore,  it is possible to remove 99.99% Cu2 by converting it to Cu(s) because the reaction is a spontaneous reaction.  

7 0
2 years ago
26.5 g of a solution with a density of 7.48 g/mL
Cloud [144]

Answer:  Assuming the question: 3.54 ml (3 sig figs)

Explanation:

I don't see a question, but will assume it is "What volume is needed to obtain 26.5 grams?

If so:

(26.5 g)/(7.48 ml) = 3.54 ml (3 sig figs)

6 0
3 years ago
what happened when potassium chloride is added to silver nitrate solutions . there no reaction B two soluble salts are formed C
Mashutka [201]

Answer:

D. One soluble and one insoluble salts are formed

Explanation:

8 0
2 years ago
A solution of silver chlorate reacts with a solution of lithium iodide.
Anettt [7]

Answer: Ag^+(aq)+I^-(aq)\rightarrow AgI(s)

Explanation:

A double displacement reaction is one in which exchange of ions take place. The salts which are soluble in water are designated by symbol (aq) and those which are insoluble in water and remain in solid form are represented by (s) after their chemical formulas.  

Spectator ions are defined as the ions which does not get involved in a chemical equation or they are ions which are found on both the sides of the chemical reaction present in ionic form.

The given chemical equation is:

AgClO_3(aq)+LiI(aq)\rightarrow AgI(s)+LiClO_3(aq)

The complete ionic equation is:

Ag^+(aq)+ClO_3^-(aq)+Li^+(aq)+I^-(aq)\rightarrow AgI(s)+Li^+(aq)+ClO_3^-(aq)

The ions which are present on both the sides of the equation are lithium and chlorate ions. and hence are not involved in net ionic equation.

Thus the net ionic equation is:

Ag^+(aq)+I^-(aq)\rightarrow AgI(s)

7 0
2 years ago
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