Sodium sulfate reacts with carbon to produce the products sodium sulfide and carbon monoxide. Identify the reducing agent in the
2 answers:
Answer : The correct option is, carbon (C)
Explanation :
Oxidizing agent : Oxidizing agent are the agent that gains electrons and is reduced in a chemical reaction.
Reducing agent : Reducing agent are the agent that lose electrons and is oxidized in a chemical reaction.
The given balanced chemical reaction is,
First we have to calculate the oxidation number of sulfur and carbon.
The oxidation state of 'S' in and
are, (+6) and (-2) respectively.
The oxidation state of 'C' in and
are, (0) and (+2) respectively.
From this we conclude that, the act as an oxidizing agent and 'C' act as a reducing agent.
Hence, the reducing agent in the following reaction is, carbon (C)
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Explanation:
As the total concentration is given as 1.2 mM. And, it is also given that salt present in the solution is NaCl.
As sodium chloride is an ionic compound so, when it is added to water then it will dissociate into sodium and chlorine ions as follows.
So, it means in total there will be formation of 2 ions when one molecules of NaCl dissociates.
Therefore, concentration of chlorine ions will be calculated as follows.
Concentration of ions =
= 0.6 mM
Thus, we can conclude that the concentration of chloride ions is 0.6 mM.