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djverab [1.8K]
3 years ago
15

Where does fusion occur?

Physics
1 answer:
inn [45]3 years ago
5 0
Maybe if you would have studied you would
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Suppose a miracle car has a 100% efficient engine and burns fuel having an energy content of 40 MJ/L. If the air resistance and
Stolb23 [73]

Answer:

Distance traveled in 1 liter = 40 km

Explanation:

Distance traveled = Energy / Opposing force = 40 x 10^6 J / 1000 N = 40000 m or 40 km

So, the car will moves to a distance of 40 km per liter under the opposing force of 1000 N…

3 0
3 years ago
A rocket is moving with constant velocity of 2000ms and accelerates uniformly at 10ms. What is the velocity after 5 minutes?
AnnyKZ [126]
The velocity is 300ml in 5 mins
8 0
3 years ago
A freight train has a mass of [02] kg. The wheels of the locomotive push back on the tracks with a constant net force of 7.50 ×
otez555 [7]

Answer:

t = 300.3 seconds

Explanation:

Given that,

The mass of a freight train, m=1.01\times 10^7\ kg

Force applied on the tracks, F=7.5\times 10^5\ N

Initial speed, u = 0

Final speed, v = 80 km/h = 22.3 m/s

We need to find the time taken by it to increase the speed of the train from rest.

The force acting on it is given by :

F = ma

or

F=\dfrac{m(v-u)}{t}\\\\t=\dfrac{m(v-u)}{F}\\\\t=\dfrac{1.01\times 10^7\times (22.3-0)}{7.5\times 10^5}\\\\t=300.3\ s

So, the required time is 300.3 seconds.

4 0
3 years ago
An 85.0-kg mountain climber plans to swing down, starting from rest, from a ledge using a light rope 6.50 m long. he holds one e
Rainbow [258]

Understanding the given:
85 kg mountain climber
6.50 m long rope
gravity = 10m/s2

If we want to identify the work done on this scenario 
we get f = 85kg x 10m/s2 = 850 N
w = 850N x 6.5 m = 5525 J

Thank you for your question. Please don't hesitate to ask in Brainly your queries. 
4 0
3 years ago
The slider of mass m is released from rest in position A and slides without friction along the vertical-plane guide shown. Deter
Anuta_ua [19.1K]

The value of normal force as the slider passes point B is

  • 6 mg

The value of h when the normal force is zero

  • 3R/2

<h3>How to solve for the normal force</h3>

The normal force is calculated using the work energy principle which is applied as below

K₁ + U₁ = K₂

k represents kinetic energy

U represents potential energy

the subscripts 1,2 , and 3 = a, b, and c

for 1 to 2

K₁ + W₁ = K₂

0 + mg(h + R) = 0.5mv²₂

g(h + R) = 0.5v²₂

v²₂ = 2g(1.5R + R)

v²₂ = 2g(2.5R)

v²₂ = 5gR

Using summation of forces at B

Normal force, N  = ma + mg

N = m(a + g)

N = m(v²₂/R + g)

N = m(5gR/R + g)

N = 6mg

for 1 to 3

K₁ + W₁ = K₃ + W₃

0 + mgh = 0.5mv²₃ + mgR

gh = 0.5v²₃ + gR

0.5v²₃ = gh - gR

v²₃ = 2g(h - R)

at C

for normal force to be zero

ma = mg

v²₃/R = g

v²₃ = gR

and v²₃ = 2g(h - R)

gR = 2gh - 2gR

gR + 2gR = 2gh

3gR = 2gh

3R/2 = h

Learn more about normal force at:

brainly.com/question/20432136

#SPJ1

8 0
1 year ago
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