1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Norma-Jean [14]
3 years ago
14

Two Carnot air conditioners, A and B, are removing heat from different rooms. The outside temperature is the same for both rooms

, 317 K. The room serviced by unit A is kept at a temperature of 293 K, while the room serviced by unit B is kept at 296 K. The heat removed from either room is 4330 J. For both units, find (a), (b) the magnitude of the work required and (c), (d) the magnitude of the heat deposited outside for A and B conditioners respectively.
Physics
1 answer:
amid [387]3 years ago
8 0

Answer:

a) Work required for air conditioner A = 354.7 J

b) Work required for air conditioner B = 310.3 J

c) The magnitude of the heat deposited outside for conditioner A = 4684.7 J

d) The magnitude of the heat deposited outside for conditioner B = 4640.3 J

Explanation:

In a carnot air conditioner, it operates like a reverse carnot engine; i.e. it removes heat from the cold reservoir (making it colder) and dumps the heat in the hot reservoir (making it hotter)

For a Carnot air conditioner,

Q꜀ is the heat removed from the colder reservoir = 4330 J for both cases

T꜀ is the temperature of the colder reservoir (temperature of the rooms) = 293 K and 296 K for both cases to be considered.

Qₕ is the heat deposited in the warmer reservoir = ? for both cases

Tₕ is the temperature of the hot reservoir (temperature of outside) = 317 K for both cases.

For Carnot air conditioners,

Qₕ = W + Q꜀ (eqn 1)

And

(Qₕ/Tₕ) - (Q꜀/T꜀) = 0 (eqn 2)

Making Qₕ the subject of formula in eqn 2

Qₕ = Tₕ (Q꜀/T꜀)

Substituting this into eqn 1

Tₕ (Q꜀/T꜀) = W + Q꜀

Q꜀ (Tₕ/T꜀) - Q꜀ = W

Q꜀ [(Tₕ - T꜀)/T꜀ ] = W

W = Q꜀ [ (Tₕ - T꜀)/T꜀ ]

For the air conditioner A,

T꜀ = 293 K, Tₕ = 317 K, Q꜀ = 4330 J, W = ?

W = Q꜀ [ (Tₕ - T꜀)/T꜀ ] = 4330 [ (317 - 293)/293] = 354.7 J

For the air conditioner B,

T꜀ = 296 K, Tₕ = 317 K, Q꜀ = 4330 J, W = ?

W = Q꜀ [ (Tₕ - T꜀)/T꜀ ] = 4330 [ (317 - 296)/296] = 310.3 J

c) Qₕ = W + Q꜀

For conditioner A,

Qₕ = 354.7 + 4330 = 4684.7 J

For conditioner B,

Qₕ = 310.3 + 4330 = 4640.3 J

You might be interested in
How much time elapses before the two kittens collide
geniusboy [140]

Answer:

6.8 s

Explanation:

Let's say the west end of the field is position 0 m and the east end of the field is position 250 m.

The position of kitten A is:

x = 0 + 25 t

And the position of kitten B is:

x = 250 - 12 t

The kittens collide when they have the same position:

25 t = 250 - 12 t

37 t = 250

t ≈ 6.8 s

3 0
3 years ago
Which of the following represents a system that is completely open
Softa [21]
The boiling pot of water is completely open 
4 0
3 years ago
Read 2 more answers
Please select the word from the list that best fits the definition
Elenna [48]

Answer:

Hi... Your answer is impulse

8 0
3 years ago
It takes 3.0 eV of energy to excite an electron in a 1-dimensional infinite well from the ground state to the first excited stat
valentina_108 [34]

Answer:

0.614 nm

Explanation:

Energy of the nth state of one dimensional infinite wall is,

E=\frac{n^{2} h^{2} }{8mL^{2} }

Given the energy to excite an electron from ground state to first excited state is,

\Delta E=3eV\\\Delta E=3(1.6\times10^{-19})J

And the Plank's constant is, h=6.626\times10^{-34}Js

Mass of electron,m=9.1\times10^{-31}kg

Now the energy will of a 1 dimensional infinite wall which excite an electron from ground state to first excited state will be,

\Delta E=\frac{2^{2} h^{2} }{8mL^{2} } -\frac{1^{2} h^{2} }{8mL^{2} }

Put all the variables in above equation and rearrange it for L.

L^{2} =\frac{3((6.626\times10^{-34}Js)^{2} )}{8\times9.1\times10^{-31}kg\times3(1.6\times10^{-19})J} \\L^{2} =0.376922012\times10^{-18} m^{2}\\ L=0.6139\times10^{-9}m\\ L=0.614nm

Therefore the width of the box is 0.614 nm.

6 0
3 years ago
the mass of the earth is 6×10²⁴ kg and the it's radius is 6400 km . what is the mass of a man weighing 977 N in spring balance ?
Anna71 [15]

Answer:

Mass of the man = 100 kg

Explanation:

Given that,

Mass of the Earth, M = 6×10²⁴ kg

The radius of the Earth, r = 6400 km

Force on man, F = 977 N

We need to find the mass of the man. Let the mass of the man be m. The gravitational force acting between two objects is given by :

F=G\dfrac{mM}{r^2}\\\\m=\dfrac{Fr^2}{GM}\\\\m=\dfrac{977\times (6400\times 10^3)^2}{6.67\times 10^{-11}\times 6\times 10^{24}}\\\\m=99.99\ kg

or

m = 100 kg

So, the mass of the man is 100 kg.

4 0
3 years ago
Other questions:
  • 1.How long dose long term alcohol abuse affect the liver ?
    15·2 answers
  • A roller coaster car starts at a height of 90 M at Point a and is moving at a speed of 20 m per second on a later Hill at Point
    12·2 answers
  • Mike drove 70 km due west and then 100 km due east.
    8·1 answer
  • The figure shows four forces exerted on a moving box, moving at a constant speed. If the box continues to move with the same spe
    12·2 answers
  • The energy levels of an atom are occupied by ____.
    13·1 answer
  • The radius of the earth is 6378 km. What is the diameter of the earth in meters?
    9·1 answer
  • 2
    8·1 answer
  • In a large restaurant an average 60% customers ask for water with their meal. A random sample of 10 customers is selected. Find
    11·1 answer
  • g The tires of a car make 75 revolutions as the car reduces its speed uniformly from 91 km/h to 48 km/h . The tires have a diame
    14·1 answer
  • What can we say about Gamma waves on<br> the electromagnetic spectrum?
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!