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Art [367]
3 years ago
11

A tennis player hits a 1.45 kg tennis ball with a racket of mass 2.5 kg. If he hits the ball with a velocity of 7.5 m/s and then

stops, what impulse did he imply on the ball? What is the ball’s velocity?
Physics
1 answer:
Marta_Voda [28]3 years ago
3 0
I = mΔv
I = 2.5 x (7.5 - 0) = 18.75 kg.m/s

Now, considering that the ball´s initial velocity was zero, we have:

1.45 x 0 + 2.5 x 7.5 = 1.45 x V
1.45V = 18.75
V = 12.93 m/s

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There is one mistake in the question.The Correct question is here

A cat falls from a tree (with zero initial velocity) at time t = 0. How far does the cat fall between t = 1/2 and t = 1 s? Use Galileo's formula v(t) = −9.8t m/s.

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Given data

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To find

Distance

Solution

As the acceleration as first derivative of velocity with respect to time  

So

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Solve it

dv  =  a dt

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v - v₀  =  -gt

v=  dy/dt

dy  =  v dt

dy =  ( v₀ - gt ) dt

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y1s - y1/2s  = ( - 4.9 m/s² ) ( 3/4 s² )

y(1s) - y(1/2s) =  - 3.675 m  

The cat falls 3.675 m between time 1/2 s and 1 s.

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The spinning of Earth's outer core causes the lithosphere to break into individual plates and collide with each other.

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