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QveST [7]
3 years ago
7

Identify and explain how the central nervous system is supported and protected.

Physics
2 answers:
s344n2d4d5 [400]3 years ago
8 0
The central nervous system is the spinal cord and brain, essentially.  It is supported and protected by the spine and the cranium, with extra cushioning and protection provided by the cerebro-spinal fluid.
PtichkaEL [24]3 years ago
3 0

Answer:

The Central Nervous System, or CNS, is literally the hardware and software that leads our entire human body. Without it, we would simply not be alive. Just like a control tower, but with the power to actually control, and not just guide, the CNS is vital and central to all the functions carried out by the body. It is also central for human beings to be able to interact with, understand, and react, to the environment that surrounds them. So the CNS does not just control our bodily functions, but also, the entire cognitive process that makes us who, and what, we are as people.

But our CNS is not just its two main components: the brain and the spinal cord. In fact, these two organs are highly dependent not just on one another, but also on other organs, systems and tissues, to be able to function properly. In fact, without these other systems, organs and tissues, the brain and spinal cord would be absolutely useless. As such, our CNS depends on nerves, both central and peripheral, that are essentially parts of the main cellular unit of the CNS, the neuron. But these neurons are extremely vulnerable and easy to damage, and therefore, they need to be protected. As such, the CNS in its entirety is protected by bone, muscle, articulations, adipose tissue, epithelial coverings, vasculature and fluid, as well as the flesh that covers our bodies.

So from the outside in, we first have skin, which essentially surrounds our entire bodies. Since the CNS is basically harbored on our spines at our backs, and on the back of our skulls, these are protected by skin. Then we have adipose tissue, which helps overall to maintain temperature and also to protect our bodies from environmental impact, as well as maintain our energy going. Then we have our blood vessels. Vasculature is central to the CNS, as it will provide it with the most needed glucose, the preferred source of energy for the CNS. It will also provide oxygen and take away waste. Then we have muscles, especially in the back, that will permit movement, while maintaining enough stability so that our spinal cord is not damaged. Then we have the bone structure and joints in the spinal column and the skull, which become serious plate protection against damage. They also become the tunnels through which our CNS traverses. Finally we have the meningeal coverings, a series of tissue linings that cover and protect most of the spinal cord and the brain, produce the CFS (cerebrospinal fluid which is the insulator and trauma absorption mechanism, as well as the one that maintains these organs of the CNS fed, since blood does not contact the CNS directly).

We could go even deeper, and see that what we mentioned above are only the superficial support system for the CNS. There are other cellular support systems as well, but those are even more complex.  

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Can work done=mass*acceleration*displacement(work=m*a*s)
Airida [17]

no, work is = force * distance or displacement


5 0
4 years ago
A 3.00 kg object is moving in the XY plane, with its x and y coordinates given by x = 5t³ !1 and y = 3t ² + 2, where x and y are
Hatshy [7]

Answer:

The net force acting on this object is 180.89 N.

Explanation:

Given that,

Mass = 3.00 kg

Coordinate of position of x= 5t^3+1

Coordinate of position of y=3t^2+2

Time = 2.00 s

We need to calculate the acceleration

a = \dfrac{d^2x}{dt^2}

For x coordinates

x=5t^3+1

On differentiate w.r.to t

\dfrac{dx}{dt}=15t^2+0

On differentiate again w.r.to t

\dfrac{d^2x}{dt^2}=30t

The acceleration in x axis at 2 sec

a = 60i

For y coordinates

y=3t^2+2

On differentiate w.r.to t

\dfrac{dy}{dt}=6t+0

On differentiate again w.r.to t

\dfrac{d^2y}{dt^2}=6

The acceleration in y axis at 2 sec

a = 6j

The acceleration is

a=60i+6j

We need to calculate the net force

F = ma

F = 3.00\times(60i+6j)

F=180i+18j

The magnitude of the force

|F|=\sqrt{(180)^2+(18)^2}

|F|=180.89\ N

Hence, The net force acting on this object is 180.89 N.

3 0
4 years ago
Si un ciclista se mueve a una velocidad de 5 m/s y acelera 1 m/s2, a los 10 segundos su velocidad será
MrRa [10]

Answer:

A los 10 segundos su velocidad será 15 \frac{m}{s}

Explanation:

La aceleración de un objeto es una magnitud que indica cómo cambia la velocidad del objeto en una unidad de tiempo.

En otras palabras, la aceleración relaciona los cambios de la velocidad con el tiempo en el que se producen, es decir que mide cómo de rápidos son los cambios de velocidad:

  • Una aceleración grande significa que la velocidad cambia rápidamente.
  • Una aceleración pequeña significa que la velocidad cambia lentamente.
  • Una aceleración cero significa que la velocidad no cambia.

La aceleración "a" puede ser calculada mediante la expresión:

a=\frac{vfinal - vinicial}{tiempo}

En este caso:

  • a= 1 \frac{m}{s^{2} }
  • vfinal= ?
  • vinicial= 5 \frac{m}{s}
  • tiempo= 10 s

Reemplazando:

1\frac{m}{s^{2} }=\frac{vfinal - 5\frac{m}{s} }{10 s}

Resolviendo se obtiene:

1 \frac{m}{s^{2} } *10 s= vfinal - 5 \frac{m}{s}

10 \frac{m}{s} = vfinal - 5 \frac{m}{s}

10 \frac{m}{s} + 5 \frac{m}{s} = vfinal

15 \frac{m}{s} = vfinal

<u><em>A los 10 segundos su velocidad será 15 </em></u>\frac{m}{s}<u><em></em></u>

5 0
3 years ago
An object of mass 8kg moved around the circle of radius 4m. with a constant speed of 15m/s.
Marianna [84]

Answer:

a. Angular velocity = 0.267rad/s.

b. Centripetal acceleration = 56.25m/s.

Explanation:

<u>Given the following data;</u>

Mass, m = 8kg

Radius, r = 4m

Constant speed, V = 15m/s

a. To find the angular velocity

Angular velocity = radius/speed

Substituting into the equation, we have;

Angular velocity = 4/15

Angular velocity = 0.267rad/s

b. To find the acceleration;

Centripetal acceleration = V²/r

Substituting into the equation, we have;

Centripetal acceleration = 15²/4

Centripetal acceleration = 225/4

Centripetal acceleration = 56.25m/s.

4 0
3 years ago
A 3 kg mass object is pushed 0.6 m into a spring with spring constant 210 N/m on a frictionless horizontal surface. Upon release
Svetradugi [14.3K]

Answer with Explanation:

We are given that

Mass of spring,m=3 kg

Distance moved by object,d=0.6 m

Spring constant,k=210N/m

Height,h=1.5 m

a.Work done  to compress the spring initially=\frac{1}{2}kx^2=\frac{1}{2}(210)(0.6)^2=37.8J

b.

By conservation law of energy

Initial energy of spring=Kinetic energy  of object

37.8=\frac{1}{2}(3)v^2

v^2=\frac{37.8\times 2}{3}

v=\sqrt{\frac{37.8\times 2}{3}}

v=5.02 m/s

c.Work done by friction on the incline,w_{friction}=P.E-spring \;energy

W_{friction}=3\times 9.8\times 1.5-37.8=6.3 J

8 0
4 years ago
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