All categories

3 years ago

What is the frequency of microwaves of wavelength 3 cm?

Physics

1 answer:

tiny-mole [99]3 years ago

4 0

Answer:

10 GHz

Explanation:

Applying,

v = λf.................... Equation 1

Where v = speed of microwave, λ = wavelength, f = frequency.

make f the subject of the equation

f = v/λ................ Equation 2

Note: Microwave is an electromagnetic wave, and all electromagnetic wave have the same speed, which is 3×10⁸ m/s

From the question,

Given: λ = 3 cm = 0.03 m

Constant; v = 3×10⁸ m/s

Substitute these values into equation 2

f = 3×10⁸/(0.03)

f = 10¹⁰ Hz

f = (10¹⁰/10⁹) GHz

f = 10 GHz

You might be interested in

Which is the correct definition for sea floor spreading

jok3333 [9.3K]

Seafloor spreading is a geologic process in which tectonic plates—large slabs of Earth's lithosphere—split apart from each other.

6 0

3 years ago

Read 2 more answers

Students had two batteries and two different resistors. During four trials, they build four different circuits and measure the c

Darina [25.2K]

Answer:

bhi jo bhi of gp oh oh gi IG 7u to uff do if goo td to yd do FP ae rt 7g hi pic vo icon

Explanation:

bh hi h bhi vc di oh x At jb jo iv hp of di of dr hi o hc x gh ki vc hi jo

5 0

2 years ago

A piston-cylinder device initially contains 1.4 kg saturated liquid water at 200oC. Now heat is transferred to the water until t

postnew [5]

Answer:

Explanation:

Given

mass of saturated liquid water $m=1.4\ kg$

at $200^{\circ}$ specific volume is $\nu =0.001157\ m^3\kg$ (From Table A-4,Saturated water Temperature table)

$V_1=m\nu _1$

$V_1=1.4\times 0.001157$

$V_1=1.6198\times 10^{-3}\ m^3$

Final Volume $V_2=4V_1$

$V_2=4\times (1.6198\times 10^{-3})$

$V_2=6.4792\times 10^{-3}\ m^3$

Specific volume at this stage

$\nu _2=\frac{V_2}{m}$

$\nu _2=\frac{6.4792\times 10^{-3}}{1.4}$

$\nu _2=0.004628\ m^3/kg$

Now we see the value and find the temperature it corresponds to specific volume at vapor stage in the table.

$T_2=T_1^{*}+\frac{T_2^{*}-T_1^{*}}{\alpha _2^{*}-\alpha _1^{*}}\times (\alpha _2-\alpha _1^{*})$

$T_2=370^{\circ}+\frac{373.95-370}{0.003106-0.004953}\times (0.004628-0.004953)$

$T_2=370.7^{\circ} C$

4 0

3 years ago

A spring whose spring constant is 260 lbf/in has an initial force of 100 lbf acting on it. Determine the work, in Btu, required

Readme [11.4K]

Answer:

A spring whose spring constant is 200 lbf/in has an initial force of 100 lbf acting on it. Determine the work, in Btu, required to compress it another 1 inch.

Step 1 of 4

The force at any point during the deflection of the spring is given by,

where is the initial force

and x is the deflection as measured from the point where the initial force occurred.

The work required to compress the spring is

Therefore work required to compress the spring is

The work required to compress the spring in Btu is calculated by

Where 1Btu =778

The work required to compress the spring,

eman Asked on February 19, 2018 in thermal fluid Sciences 4th solutions.

Explanation:

7 0

3 years ago

A block floats partially submerged in a container of liquid. When the entire container is accelerated upward, which of the follo

Nookie1986 [14]

Answer:C

Explanation:

Partially submerged block along with vessel is accelerated upwards .

Initially the block weight is supported by buoyant force such that it is in equilibrium.

when the system start accelerating upwards then the effective gravity will be

g+a where a is the acceleration of the system.

so only net gravity is increased so block will not ascend or descend.

Mathematically

$F_b=weight$

$\rho _L\cdot V\cdot (g+a)=m(g+a)$

where $\rho _L=$ density of liquid

V=volume of object inside the water

7 0

3 years ago