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arsen [322]
3 years ago
5

Si un ciclista se mueve a una velocidad de 5 m/s y acelera 1 m/s2, a los 10 segundos su velocidad será

Physics
1 answer:
MrRa [10]3 years ago
5 0

Answer:

A los 10 segundos su velocidad será 15 \frac{m}{s}

Explanation:

La aceleración de un objeto es una magnitud que indica cómo cambia la velocidad del objeto en una unidad de tiempo.

En otras palabras, la aceleración relaciona los cambios de la velocidad con el tiempo en el que se producen, es decir que mide cómo de rápidos son los cambios de velocidad:

  • Una aceleración grande significa que la velocidad cambia rápidamente.
  • Una aceleración pequeña significa que la velocidad cambia lentamente.
  • Una aceleración cero significa que la velocidad no cambia.

La aceleración "a" puede ser calculada mediante la expresión:

a=\frac{vfinal - vinicial}{tiempo}

En este caso:

  • a= 1 \frac{m}{s^{2} }
  • vfinal= ?
  • vinicial= 5 \frac{m}{s}
  • tiempo= 10 s

Reemplazando:

1\frac{m}{s^{2} }=\frac{vfinal - 5\frac{m}{s} }{10 s}

Resolviendo se obtiene:

1 \frac{m}{s^{2} } *10 s= vfinal - 5 \frac{m}{s}

10 \frac{m}{s} = vfinal - 5 \frac{m}{s}

10 \frac{m}{s} + 5 \frac{m}{s} = vfinal

15 \frac{m}{s} = vfinal

<u><em>A los 10 segundos su velocidad será 15 </em></u>\frac{m}{s}<u><em></em></u>

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Answer:

Explanation:

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N=W=mg

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Fr= µmg

This is the only force on the x-axis

Then,

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Divide through by m

a= -µg

The negative show that it is decelerating

So using equation of motion

V=u+at

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u is initial velocity =Vo

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V = Vo - µgt

The angular acceleration that sets the ball rotating with increasing angular velocity in anticlockwise direction whose magnitude ω, at any instant t, is given by

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Also, V=ωR

V=αtR

To get angular acceleration

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α = 5µg/2R.

From above

V = Vo - µgt, then, V=αtR

αtR= Vo - µgt

αtR + µgt= Vo

t(αR + µg)=Vo

t=Vo/(αR + µg)

Since α = 5µg/2R

t=Vo/( 5µg/2R • R + µg)

t = Vo/( 5µg/2+ µg)

t= Vo/(7µg/2)

t=2Vo/7µg

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t = 2Vo/7µg

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kifflom [539]

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Explanation:

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