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DIA [1.3K]
4 years ago
13

The answer to this problem

Mathematics
1 answer:
horrorfan [7]4 years ago
7 0
Work backwards with pythagoras' theorem:
c^2=a^2+b^2
Here, a and b both equal to x. Therefore, you can write this as 8^2=2x^2. So 64=2x^2. Sqrt on both sides to give you 8=2x, hence x=4. However I must warn you that this working out may have a flaw, as I found that x actually equals to 5.66
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Need help with this like right now, asap
Gemiola [76]

Answer:

h = 5

Step-by-step explanation:

area = 1/2 base × hight

base = 3 +h

hight =9 + 6 = 15

60 = 1/2 × 15 × (3+h)

120/15 = 3 + h

8 = 3 + h

h = 5

6 0
3 years ago
Read 2 more answers
The perimeter of a triangular pool is 36 yards. The lengths of two sides are 10 yards and 15 yards. How long is the third side?
ohaa [14]

Answer:

11 yards

Step-by-step explanation:

15+10+x=36

25+x=36

36-25=x

x=11

3 0
3 years ago
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The function f(x) is graphed below. What is true about the graph on the interval from x=−∞ to x=a?
xxMikexx [17]

Answer:

The correct answer for the question that is being presented above is this one: "The range of the function is all real numbers; The function has two x-intercepts. The statements about the graph of the function f(x) = 2x2 – x – 6 that are true includes: The range of the function is all real numbers; The function has two x-intercepts.

Step-by-step explanation:

8 0
3 years ago
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The ratio length to the width of a rectangle is 15:8 how many times the width of the rectangle I see the length of the rectangle
algol [13]
18 times lol !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
4 0
3 years ago
Please help me I would really appreciate it.
Karo-lina-s [1.5K]

Given:

\overline{AB}\cong \overline {CD},\overline{BC}\cong \overline {DA}

To prove:

\Delta CDA\cong \Delta ABC

Proof:

In \Delta CDA\text{ and } \Delta ABC,

\overline{AB}\cong \overline {CD} because Given

\overline{BC}\cong \overline {DA} because Given

\overline{AC}\cong \overline {AC} because Reflexive property.

Corresponding sides of both triangles are congruent. So,

\Delta CDA\cong \Delta ABC because SSS

Therefore, the required missing values are: Given, \overline{BC}\cong \overline {DA}, Reflexive property ,\Delta CDA\cong \Delta ABC, SSS respectively.

5 0
3 years ago
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