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miss Akunina [59]
3 years ago
13

Will give brainliest!!!!

Physics
2 answers:
charle [14.2K]3 years ago
8 0
Microwaves have higher wavelength, lower frequency and lower energy than the visible light...Hope this helps...Can you mark me brainliest?
Nezavi [6.7K]3 years ago
5 0

Hello!

Microwaves has a higher wavelength but it has a lower frequency, so it also has lower energy. Visible light has a high frequency so it also has high energy.

I hope it helps!

Brainliest?

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A student, standing on a scale in an elevator at rest, sees that his weight is 840 N. As the elevator rises, his weight increase
ololo11 [35]

As per FBD while its accelerating upwards

we can say that

F_n - mg = ma

here normal force is given as

F_n = 1050 N

W = 840 N

now mass is given as

m(9.8) = 840

m = 85.7 kg

now we will have

1050 - 840 = 85.7 \times a

a = 2.45 m/s^2

Now while accelerating downwards we can say by FBD

mg - F_n = ma

again plug in all values

840 - 588 = 85.7 \times a

a = 2.94 m/s^2

5 0
4 years ago
A mango falls fromthe top its tree passing a window which is 2.4m tall by taking 0.4s
Natasha2012 [34]

Explanation:

There are three points in time we need to consider.  At point 0, the mango begins to fall from the tree.  At point 1, the mango reaches the top of the window.  At point 2, the mango reaches the bottom of the window.

We are given the following information:

y₁ = 3 m

y₂ = 3 m − 2.4 m = 0.6 m

t₂ − t₁ = 0.4 s

a = -9.8 m/s²

t₀ = 0 s

v₀ = 0 m/s

We need to find y₀.

Use a constant acceleration equation:

y = y₀ + v₀ t + ½ at²

Evaluated at point 1:

3 = y₀ + (0) t₁ + ½ (-9.8) t₁²

3 = y₀ − 4.9 t₁²

Evaluated at point 2:

0.6 = y₀ + (0) t₂ + ½ (-9.8) t₂²

0.6 = y₀ − 4.9 t₂²

Solve for y₀ in the first equation and substitute into the second:

y₀ = 3 + 4.9 t₁²

0.6 = (3 + 4.9 t₁²) − 4.9 t₂²

0 = 2.4 + 4.9 (t₁² − t₂²)

We know t₂ = t₁ + 0.4:

0 = 2.4 + 4.9 (t₁² − (t₁ + 0.4)²)

0 = 2.4 + 4.9 (t₁² − (t₁² + 0.8 t₁ + 0.16))

0 = 2.4 + 4.9 (t₁² − t₁² − 0.8 t₁ − 0.16)

0 = 2.4 + 4.9 (-0.8 t₁ − 0.16)

0 = 2.4 − 3.92 t₁ − 0.784

0 = 1.616 − 3.92 t₁

t₁ = 0.412

Now we can plug this into the original equation and find y₀:

3 = y₀ − 4.9 t₁²

3 = y₀ − 4.9 (0.412)²

3 = y₀ − 0.83

y₀ = 3.83

Rounded to two significant figures, the height of the tree is 3.8 meters.

6 0
3 years ago
The diagram is a real world example of the first and second laws of thermodynamics. It shows how thermal energy is used to gener
Dmitriy789 [7]

Answer:

First law: kinetic energy is used to turn an electric generator

Second law: some thermal energy is lost to the environment as it travels through the system

Explanation:

The first law of thermodynamics is known as the law of conservation of energy. It states that energy can neither be created nor destroyed but can only be transferred or changed from one form to another. When thermal energy is used to generate electricity, the kinetic energy of the steam is used to turn the electric generator (thereby producing electrical energy).

The second law of thermodynamics states that energy transfer or transformation leads to an increase in entropy resulting in the loss of energy. This law also states that as energy is transferred or transformed, some is lost in a form that is unusable. When thermal energy is used to generate electricity, some of the thermal energy is lost to the environment as it travels through the system.

7 0
3 years ago
Read 2 more answers
Why cant body builders swim please give reasons.
Ronch [10]
The main reason is becouse these people are over 200 pounds and no mater how strong you are arms arnt ment to keep you up thanks.
8 0
3 years ago
Read 2 more answers
A block slides to a stop as it goes 47 m across a level floor in a time of 6.35 s. a) What was the initial velocity? b) What is
UNO [17]

Answer :

(a) The initial velocity is, 14.8 m/s

(b) The acceleration is, -2.33m/s^2

Explanation :

By the 1st equation of motion,

v=u+at     ...........(1)

where,

v = final velocity = 0 s

u = initial velocity

t = time = 6.35 s

a = acceleration

The equation 1 will be:

0=u+a(6.35}

u=-6.35a       ..........(2)

By the 2nd equation of motion,

s=ut+\frac{1}{2}at^2     ...........(3)

where,

s = distance = 47 m

Now substitute equation 2 in 3, we get:

47=(-6.35a)\times (6.35)+\frac{1}{2}\times a\times (6.35)^2

By solving the term, we get:

a=-2.33m/s^2

The acceleration is, -2.33m/s^2

Now we have to calculate the initial velocity.

Using equation 2, we gte:

u=-6.35a

u=-6.35s\times (-2.33m/s^2)

u=14.8m/s

The initial velocity is, 14.8 m/s

5 0
3 years ago
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