Heat Transfer, Specific Heat. and CalorimetryA 1.28-kg sample of water at 10.0 "C is in a calorimeter. You drop a piece of steel
with a mass of 0.385 kg at 215 "C into it.After the sizzling subsides, what is the final equilibrium temperature? (Make the reasonable assumptions that any steamproduced condenses into liquid water during the process of equilibration and that the evaporation and condensation don’taffect the outcome. as we’ll see in the next section.)
Since the four metallic objects are identical, and total charge must be conserved, this means that after brought simultaneously into contact so that each touches the others, once separated, total charge must be the same than before being brought in contact.
But due they are identical, after charges were able to transfer freely between them, the four objects must have the same final charge, i.e. the fourth part of the total charge, as follows:
b)
This charge will be divided between n protons, since the charge is positive.
Since each proton carries a charge equal to the elementary charge e, which value is 1.6*10⁻¹⁹ C, we can find the number of protons in excess, doing the following calculation:
G/mL is equivalent to g/cm^3, so we first convert the dimensions into cm: 2.20 cm, 1.35 cm, and 1.25 cm Then the total volume is: V = lwh = 3.7125 cm^3 To get the density, we divide mass by volume: 2.50 g / 3.7125 cm^3 = 0.6734 g/cm^3 = 0.6734 g/mL
