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Tju [1.3M]
2 years ago
11

During the first stage of sleep deprivation, the subject may __________.

Physics
2 answers:
klio [65]2 years ago
7 0
<h2>First stage of sleep Deprivation Subject </h2>

During the first stage of sleep deprivation, the subject is NREM which stands for non-rapid eye movement. In this condition, we are not sleeping in the depth. It can be said as dreamless sleep. On electro-encephalography recording, the brain waves are not fast so they have high voltage.

In this condition, the breathing, heart rate and blood pressure is low. The sleep is comparatively tranquil. NREM lasts for 90 minutes to 120 minutes. It accounts for about 75% of the normal sleep time. Rapid eye movements do not occur.


Tasya [4]2 years ago
5 0

Answer:

During the first stage of sleep deprivation the subject will become moody, grumpy or irritable.

Explanation:

There are two kinds of sleep deprivation which are classified as acute and chronic sleep deprivation. The acute one is the kind in which patient cannot sleep for one or two nights but in chronic sleep deprivation patient miss the seven hours of sleep per night in a week.

Dr. Ruiz further classified the stages of sleep deprivation as:

  • Moodiness and irritability.
  • Difficulty in concentrating.
  • Difficulty in naming things.
  • Lapse in memory.
  • Hallucination.
  • Paranoia
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3 years ago
A very good insulator has an R-value of 29. The material's heat transfer coefficient is
Fittoniya [83]

Answer:

b. 0.034

Explanation:

The heat transfer coefficient of a material (U-value) is equal to the reciprocal of its R-value, therefore:

U = \frac{1}{R}

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For the insulator in this problem,

R = 29

Substituting into the equation, we find the heat transfer coefficient:

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2 years ago
The Doppler effect is a change in the ________________ frequency of sound caused by the motion of either their listener or the s
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Read 2 more answers
Monochromatic light of wavelength 580 nm passes through a single slit and the diffraction pattern is observed on a screen. Both
Nuetrik [128]

Answer:

Part a)

Width of the slit is

a = 580 nm

Part b)

Ratio of intensity is given as

\frac{I}{I_o} = 0.81

Explanation:

Part a)

As we know by the formula of diffraction we will have

a sin\theta = \lambda

so we have

\theta = 90

\lambda = 580 nm

so we will have

a sin90 = 580 nm

a = 580 nm

Part b)

As we know that the intensity in diffraction pattern is given as

I = I_o (\frac{sin\theta}{\theta})^2

\frac{I}{I_o} = (\frac{sin\theta}{\theta})^2

so for angle 45 degree

\frac{I}{I_o} = (\frac{sin45}{\pi/4})^2

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\frac{I}{I_o} = 0.81

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3 years ago
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