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3 years ago

Whats it called when a force can change the shape of an object?

Physics

2 answers:

mario62 [17]3 years ago

5 0

Answer:

Explanation: Blowing is a kind of force (push). Force can change the shape and size of an object. Example: shape or size of a spring changes on pulling or pushing it. Pulling increases it’s length while pus

ing decreases it’s length.

alekssr [168]3 years ago

3 0

Force applied causes deformation in the object. It changes the relative positions of constituent particles in the crystal lattice.
As soon as that happens, the interatomic or intermolecular forces come into play and they, tend to restore the solid back to it's original shape.

This restoring force per unit area is called Stress . When external forces are removed, the internal forces tend to restore the solid back.
This property is called Elasticity .

However, no material is perfectly elastic and what happens is that, the body is not able to restore itself completely.

You might be interested in

When turned on, a fan requires 5.0 seconds to get up to its final operating rotational speed of 1200 rpm. a) How large is the fi

vova2212 [387]

Answer:

125.6 rad/s

25.12 rad/s²

Explanation:

t = time required by the fan to get up to final operating speed = 5 sec

w = final operating rotational speed = 1200 rpm

we know that :

1 revolution = 2π rad

1 min = 60 sec

w = $1200\frac{rev}{min}\frac{2\pi rad}{1 rev}\frac{1 min}{60 sec}$

w = $\frac{1200\times 2\pi }{60}\frac{rad}{s}$

w = 125.6 rad/s

w₀ = initial angular speed = 0 rad/s

α = angular acceleration

using the equation

w = w₀ + α t

125.6 = 0 + α (5)

α = 25.12 rad/s²

5 0

3 years ago

A boy whirls a stone in a horizontal circle of radius 1.1 m and at height 2.1 m above ground level. The string breaks, and the s

DedPeter [7]

Answer:

$212.8 m/s^{2}$

Explanation:

Time taken by stone to cover horizontal distance

$t=\sqrt{\frac {2h}{g}}$ where t is time, h is height of whirling the stone in horizontal circle, g is gravitational constant, Substituting h for 2.1 m and g for 9.81

$t=\sqrt{\frac {2*2.1}{9.81}}$ = 0.654654 seconds

t=0.65 s

Velocity, v= distance/time

v=10/0.65= 15.27525 m/s

v=15.3 m/s

$a=\frac {v^{2}}{r}$ where r is radius of circle, substituting r with 1.1m

$a=\frac {15.3^{2}}{1.1}$

$a=212.8 m/s^{2}$

Therefore, centripetal acceleration is $212.8 m/s^{2}$

8 0

3 years ago

Describe a situation in your everyday life where you could use the scientific method. List all the steps of the scientific metho

emmainna [20.7K]

Yes, scientific method can be applied on many everyday activities to get a reasonable solution. Infact normally we are applying this method without having it in our knowledge that we are applying it.

For example: In morning we are going to office and we start the car, but it is not started.You turn the engine again and again but it simply donot works.

Observation (the state of defining a problem):

The car is not started

Hypothesis (A possible solution based on the information we already know):

The car is not started because it might be out of gas or there can be some other technical fault.

Experiment (testing of hypothesis by applying different methods of solving problem):

You get the fuel and put it inside the car but it still donot works and car didnot start. Experiment didnot get solution.

Analyze the results of data and test another hypothesis

You call a technician and he check with the car engine tries and finds out that the engine was out of order and needs repairing.

Draw conclusion:

The engine do not works when it is out of order and it is a cause of a car not being started.

Now the theory and law making part can not be applied on this case but it is a part of scientific method.

Hope it helps!

8 0

3 years ago

By the 2nd century BCE the ____ democratized astrology A. Greeks B. Egyptians C. Romans

elena-14-01-66 [18.8K]

Answer:

Explanation:

3 0

3 years ago

What is the repulsive force between two pith balls that are 8.00 cm apart and have equal charges of −25.0 nc? g?

Daniel [21]

To calculate the force between two negative charges, we use the formula which is given by the Coulomb`s Law as

$F=\frac{kq_{1}q_{2} }{r^{2} }$

Here, $q_{1}$ and $q_{2}$ are the charges on the pith balls, r is the separation between the charges and k is constant and its value is $8.99\times 10^9 N m^2/C^2$ .

Given $q_{1} =q_{2} =-25 nC=-25\times 10^{-9}C$ and $r=8 cm=8\times10^{-2} m$ .

Substituting these values in above formula we get,

$F= 8.99\times 10^9 N m^2/C^2\frac{(-25\times 10^{-9}C)(-25\times 10^{-9}C)}{(8\times10^{-2} m)^2} \\\\\ F= 877929.7\times 10^{-9} N\\\\F=8.8\times10^{-4}N$

Thus, the repulsive force between two pith balls is $8.8\times10^{-4}N$ .

7 0

3 years ago

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