Answer:
R=4Ω
Explanation:
R1 and R3 are parrallel
so we have : R=R1*R2/R1+R2
R=6*3/6+3
R=18/9
R=2Ω
R2 and 2Ω are in series,so we have
R=R2+2
R=2+2
R=4Ω
Answer:
A. 52 min
.A. 47 watts
Explanation:
Given that;
jim weighs 75 kg
and he walks 3.3 mph; the objective here is to determine how long must he walk to expend 300 kcal.
Using the following relation to determine the amount of calories burned per minute while walking; we have:

here;
MET = energy cost of a physical activity for a period of time
Obtaining the data for walking with a speed of 3.3 mph From the standard chart for MET, At 3.3 mph; we have our desired value to be 4.3
However;
the calories burned in a minute = 
= 5.644
Therefore, for walking for 52 mins; Jim burns approximately 293.475 kcal which is nearest to 300 kcal.
4.
Given that:
mass m = 75 kg
intensity = 6 kcal/min
The eg ergometer work rate = ??
Applying the formula:

where ;



∴
Converting to watts;
Since; 6.118kg-m/min is = 1 watt
Then 291.66 kgm /min will be equal to 47.67 watts
≅ 47 watts
Answer:
Acceleration
Explanation:
Acceleration is the change in velocity/speed per unit time
<span>29 Newtons
Centripetal force is modeled by the equation:
F = MV^2/R
where
F = force
M = Mass
V = Velocity
R = Radius
I will assume the shark is swimming in a circle with a radius of 14 m / 2 = 7 m. The actual radius will be smaller, but I'll assume that the question is simply poorly worded. So we need to calculate the velocity of the shark. The circumference of the circle is pi*14m = 43.98229715 m. And since velocity is defined as distance over time, we have a velocity of 43.98229715 m / 80 s = 0.549778714 m/s.
Now substitute the known values into the equation for centripetal force.
F = MV^2/R
F = 681 kg * ( 0.549778714 m/s)^2 / 7m
F = 681 kg * 0.302256635 m^2/s^2 / 7m
F = 205.8367683 kg*m^2/s^2 / 7m
F = 29.40525261 kg*m/s^2
F = 29.40525261 N
Rounding to 2 significant figures gives a force of 29 Newtons.</span>