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Advocard [28]
4 years ago
8

Nitroglycerin is a dangerous powerful explosive that violently decomposes when it is shaken or dropped. The Swedish chemist Alfr

ed Nobel (1833-1896) founded the Nobel Prizes with a fortune he made by inventing dynamite, a mixture of nitroglycerin and inert ingredients that was safe to handle.
Write a balanced chemical equation, induding physical state symbols, for the decomposition of liquid nitroglycerin into gaseous dinitrogen, gaseous dloxygen, gaseous water and gaseous carbon dioxide.
Chemistry
1 answer:
marshall27 [118]4 years ago
3 0

<u>Answer:</u> The balanced chemical equation for the decomposition of nitroglycerin is written below.

<u>Explanation:</u>

Decomposition reaction is defined as the reaction in which a single large substance breaks down into two or more smaller substances.

Every balanced chemical equation follows law of conservation of mass.

A balanced chemical equation is defined as the equation in which total number of individual atoms on the reactant side is equal to the total number of individual atoms on product side.

The balanced chemical equation for the decomposition of nitroglycerin follows:

4C_3H_5N_3O_9(l)\rightarrow 12CO_2(g)+10H_2O(g)+6N_2(g)+O_2(g)

By Stoichiometry of the reaction:

1 mole of liquid nitroglycerin decomposes into 12 moles of carbon dioxide gas, 10 moles of gaseous water, 6 moles of dinitrogen gas and 1 mole of dioxygen gas.

Hence, the balanced chemical equation for the decomposition of nitroglycerin is written above.

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Dude... h2o, thats why ICE FLOATS ON WATER!!!!

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4 years ago
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Given the half‑reactions and their respective standard reduction potentials 1. Cr 3 + + e − ⟶ Cr 2 + E ∘ 1 = − 0.407 V 2. Cr 2 +
Licemer1 [7]

Answer:

The standard reduction potential for the reduction half‑reaction of Cr(III) to Cr(s) is -0.744 V

Explanation:

Here we have

1. Cr³⁺  + e − ⟶ Cr²⁺ E⁰₁ = − 0.407 V

2. Cr²⁺ + 2 e − ⟶ Cr ( s ) E⁰₂  = − 0.913 V

To solve the question, we convert, the E⁰ values to ΔG as follows

ΔG₁ = n·F·E⁰₁ and ΔG₂ = n·F·E⁰₂

Where:

F = Faraday's constant in calories

n = Number of e⁻

ΔG₁ = Gibbs free energy for the first reaction

ΔG₂ = Gibbs free energy for the second half reaction

E⁰₁  = Reduction potential for the first half reaction

E⁰₂ = Reduction potential for the second half reaction

∴ ΔG₁ = 1 × F × − 0.407 V

ΔG₂ = 2 × F  × − 0.913 V

ΔG₁  + ΔG₂  = F × -2.233 V which gives

ΔG = n × F × ΔE⁰ = F × -2.233 V  

Where n = total number of electrons ⇒ 1·e⁻ + 2·e⁻ = 3·e⁻ = 3 electrons

We have, 3 × F × ΔE⁰ = F × -2.233 V

Which gives ΔE⁰ = -2.233 V /3 = -0.744 V.

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Answer:

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Explanation:

Step 1: Write the balanced equation

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Step 2: Establish the appropriate molar ratio

According to the balanced equation, the molar ratio of NH₄NO₃ to N₂O is 1:1.

Step 3: Calculate the number of moles of N₂O formed upon complete reaction of 0.192 moles of NH₄NO₃

We will use the previously established molar ratio.

0.192 mol NH₄NO₃ × 1 mol N₂O/1 mol NH₄NO₃ = 0.192 mol N₂O

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Hope this was helpful!

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