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Elan Coil [88]
2 years ago
11

How many moles of aluminum ions are present in 0.34 moles of Al2(SO4)3?

Chemistry
1 answer:
IceJOKER [234]2 years ago
7 0

Answer:

We need 0.68 moles of aluminium ions to be present to make 0.34 moles Al2(SO4)3

Explanation:

Step 1: Data given

Number of moles Al2(SO4)3 = 0.34 moles

Step 2: The balanced equation

2Al + 3H2SO4 = Al2(SO4)3 + 3H2

Step 3: Calculate the number of moles aluminium ions

For 2 moles we need 3 moles H2SO4 to produce 1 mol Al2(SO4)3 and 3 moles H2

For 0.34 moles Al2(SO4)3 we need 2*0.34 = 0.68 moles aluminium

We need 0.68 moles of aluminium ions to be present to make 0.34 moles Al2(SO4)3

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2H2 + O2 → 2H2O
pantera1 [17]
Okay
Mr (H2O)= 18g
therefore moles of H2O
is 720.8/18= 40.04mol
the ratio of H2 to O2 to H2O is
2 : 1 : 2
so moles of H2 is same as H2O here
H2= 40.04moles

moles of O2 is half
so 40.04 x 0.5
20.02moles

grams of O2 is
its moles into Mr of O2
that's 20.02 x 32 = 640.64g

6 0
2 years ago
As a storm from moves in, you notice that a column of mercury in a barometer rises to 736 mm. (a) Determine the air pressure. (b
sesenic [268]

Answer:

The air pressure is 9.8 *10^4 pa

The water will rise to a height of 10.0 meter

Explanation:

Step 1: Data given

As a storm from moves in, you notice that a column of mercury in a barometer rises to 736 mm.

Step 2: Calculate the air pressure

The Pressure against the mercury column = h*d*g = 0.736 * 13593 * 9.81 = 9.8 * 10^4 Pa

Step 3: Calculate the height of the water

Let the Pressure  the water column for same pressure is h meter : -

9.8 * 10^4 = h*d*g  

=>9.8*10^4 = h*1000*9.81  

=>h = 10.0 meter

The water will rise to a height of 10.0 meter

5 0
3 years ago
Acids which contain only hydrogen and a single other element are referred to as.
Pachacha [2.7K]

\huge{\green}\fcolorbox{blue}{cyan}{\bf{\underline{\red{\color{red}Answer}}}}

  • A binary acid is an acid that consists of hydrogen and one other element.
8 0
2 years ago
A mixture of c2h2 and ch4 has a total mass of 230.9 g. when this mixture reacts completely with excess oxygen, the co2 and h2o p
Salsk061 [2.6K]
Interesting problem. Thanks for posting.

C2H2 + (3/2)02 ====>  H2O + 2CO2
CH4 +  2O2 =====> 2H2O + CO2

The molar mass of C2H2 = 2*12 + 2*1 = 26
The molar mass of CH4 = 1*12 + 4*1 = 16

The number of moles of C2H2 = x
The number of moles of  CH4 = y
26x + 16y = 230.9 grams

For water we get (from the C2H2). Water has a molar mass of 2*1 + 16 = 18

x*18 See the balanced equation to see what it is the same number of moles as C2H2
From the methane we get
y*18
2*y* 18. Again see the balanced equation to see where that 2 came from.
18x + 36y is the total amount of water. 

Now for the CO2. CO2 has a molar mass of 12 + 2*16 = 44
From C2H2  we get 2*44*x = 88x grams of CO2
From CH4 we get 1*y*44 grams of CO2
88x + 44y for CO2

Now we total to get the grand total of water and CO2
18x + 44y + 88x + 44y = 972.7 grams total.
106x + 88y =  972.7

Two equations, two unknowns, we should be able to solve this problem
26x + 16y = 230.9
106x + 88y = 972.7

I'm not going to go through the math unless you request me to do so. 
x = 8.03 moles
y = 1.38 moles 

The initial amount of C2H2 was 8.03 * 26 = 208.78
The initial amount of CH4 was 16*1.38 = 22.08
The total (as a check is 230.86 which is pretty close to the given amount.
So Methane's mass in the initial givens was 22.08 grams.
6 0
2 years ago
For each of the following units and concentration values, mention if they are parts per million (ppm), parts per billion (ppb) o
arsen [322]

Answer:

a) ppm

b) ppm

c) ppb

d) ppt

e) ppb

Explanation:

a) You know that 1000 g are 1 kg, and 1000 kg are 1 ton, so (1000)*(1000) g are 1 ton, so 1,000,000 grams are one ton.

b) 1000 mg are 1 g, and 1000 g are 1 liter, so 1,000,000 grams are one liter.

c) You know that 1000 ug are 1 mg, so with the b), we just need to multiply the answer by 1000, so 1,000,000,000 ug are 1 liter.

d) The same as c, 1000 ng are 1 mg. So we are talkinf of ppt.

e) 1000 mg are 1 g. And 1000 g are 1 kg, then 1000 kg are one ton. So 1,000,000,000 mg are one ton.

7 0
3 years ago
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