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3 years ago

The reason why iodine sublimes

1 answer:

7 0

The intermolecular forces for Iodine are much lower than the energy needed to free it from its crystal lattice. Once Iodine has enough energy to break out of the lattice, it also has enough energy to separate from its neighbors. And so, it sublimes.

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Which way of dissolving changes the chemical identity of the solute?

sasho [114]

Answer:

Ionization and dissociation

5 0

3 years ago

Read 2 more answers

After throwing the ball in the pool for my dog the ball sprung a leak and begin to fill with water. How many mL of water can th

ikadub [295]

Answer: i think 250ML

Explanation:

5 0

3 years ago

Calculate the number of moles of H2 produced in the reaction of Mg(s) with HCl(aq). Mg(s) is the

Taya2010 [7]

Explanation:

Moles of metal,

4.86

⋅

24.305

⋅

−

0.200

Moles of

100

⋅

−

2.00

⋅

−

0.200

Clearly, the acid is in deficiency ; i.e. it is the limiting reagent, because the equation above specifies that that 2 equiv of HCl are required for each equiv of metal.

So if

0.200

acid react, then (by the stoichiometry), 1/2 this quantity, i.e.

0.100

of dihydrogen will evolve.

So,

0.100

dihydrogen are evolved; this has a mass of

0.100

⋅

2.00

⋅

−

If 1 mol dihydrogen gas occupies

24.5

at room temperature and pressure, what will be the VOLUME of gas evolved?

5 0

2 years ago

A 7.0 g sample of a hydrocarbon (a molecule that has only hydrogen and carbon) is subject to combustion analysis. The mass of CO

Akimi4 [234]

Answer: The empirical formula for the given compound is $CH_2$

Explanation:

The chemical equation for the combustion of compound having carbon and hydrogen follows:

$C_xH_y+O_2\rightarrow CO_2+H_2O$

where, 'x' and 'y' are the subscripts of carbon and hydrogen respectively.

We are given:

Mass of $CO_2=22.0g$

We know that:

Molar mass of carbon dioxide = 44 g/mol

For calculating the mass of carbon:

In 44 g of carbon dioxide, 12 g of carbon is contained.

So, in 22.0 g of carbon dioxide, $\frac{12}{44}\times 22.0=6g$ of carbon will be contained.

For calculating the mass of hydrogen:

Mass of hydrogen = Mass of sample - Mass of carbon

Mass of hydrogen = 7.0 g - 6 g

Mass of hydrogen = 1.0 g

To formulate the empirical formula, we need to follow some steps:

Step 1: Converting the given masses into moles.

Moles of Carbon = $\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{6g}{12g/mole}=0.5moles$

Moles of Hydrogen = $\frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{1.0g}{1g/mole}=1.0moles$

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.5 moles.

For Carbon = $\frac{0.5}{0.5}=1$

For Hydrogen = $\frac{1.0}{0.5}=2$

Step 3: Taking the mole ratio as their subscripts.

The ratio of Fe : C : H = 1 : 2

Hence, the empirical formula for the given compound is $C_{1}H_{2}=CH_2$

4 0

3 years ago

The isomerization reaction, ch3nc → ch3cn, is first order and the rate constant is equal to 0.46 s-1 at 600 k. what is the conce

Harlamova29_29 [7]

According to this formula :
㏑[A] /[Ao] = - Kt
when we have Ao = 0.3 m
and K =0.46 s^-1
t = 20min = 0.2 x 60 =12 s
So by substitution :
㏑[A] / 0.3 = - 0.46 * 12
㏑[A] / 0.3 = - 5.52
by taking e^x for both side of the equation we can get [A]
∴[A] = 0.0012 mol dm^-3

6 0

3 years ago