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MrRa [10]
3 years ago
4

The friends recently learned that when light from the Sun hits our atmosphere from the vacuum of interplanetary space, it is ref

racted, much like a beam of light passing from air to water. Tristan asks Camilla how this affects the apparent rising and setting times of the Sun. Which response is correct?
(A) "The Sun appears to rise sooner, and set later than it actually does."
(B) "The apparent rising and setting times of the Sun are completely unaffected by refraction."
(C) "The Sun appears to rise sooner, and set sooner than it actually does."
(D) "The Sun appears to rise later, and set later than it actually does."
Physics
1 answer:
wel3 years ago
7 0

Answer:

(A) "The Sun appears to rise sooner, and set later than it actually does."

Explanation:

The correct answer is

(A) "The Sun appears to rise sooner, and set later than it actually does."

This happens mainly due to refraction of the sun light as it travels from the vacuum of interplanetary space, it is refracted, much like a beam of light passing from air to water. This causes a bend in direction of light rays and what we see is a false or an apparent image.

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Calcular la aceleración que produce una fuerza de 40 N sobre un cuerpo con 88 Kg de masa. Expresar el resultado en m⁄s^2 *
tigry1 [53]

Answer:

a = 0.45 m/s²

Explanation:

The given question is ''Calculate the acceleration that produces a force of 40 N on a body with 88 kg of mass".

Given that,

Force, F = 40 N

Mass of the body, m = 88 kg

The net force acting on the body is given by :

F = ma

Where

a is the acceleration of the body

a=\dfrac{F}{m}\\\\a=\dfrac{40\ N}{88\ kg}\\\\a=0.45\ m/s^2

So, the required acceleration is 0.45 m/s².

4 0
3 years ago
Plsss helpp will give brainliest!!!
Alexandra [31]

Answer:

1. Flexibility.

2. Muscular Fitness

3. Cardiovascular Fitness

4. Cardiovascular Fitness

5. Flexibility

6. Muscular Fitness

7. Cardiovascular Fitness

6 0
3 years ago
Two 5.0-cm-diameter conducting spheres are 8.0 m apart, and each carries 0.12 mC. Determine (a) the potential on each sphere, (b
blagie [28]

Answer:

Explanation:

Two spheres 10m apart

Each charge on the sphere is 0.12mC= 0.12×10^-3C

Given that the diameter is

5cm=0.05m

Then, the radius is diameter / 2

r=d/2

r=0.05/2

r=0.025m

Potential is given as

V=kq/r

k=9×10^9Nm2/C2

a. Potential on each sphere surface.

They are going to have the same value since the sphere are identical

At the surface of the sphere,

r= 0.025m

V=kq/r

V=9E9×0.12E-3/0.025

V=4.32E7Volts

V=4.32×10^7Volts

b. The electric field at the surface of each sphere will be the same since the charge are identical,

So, Electric field is given as

E=kq/r^2

At the surface

E=9E9×0.12E-3/0.025^2

E=1.728×10^8N/C

c. The potential mid way between the two sphere

The potential difference due to the first sphere

The sphere are 10m apart then the distance mid way is 5m

Then, the radius of the sphere is 0.025m

Total distance from the center is 5.025m

Then,

V=kq/r

V1=9E9×0.12E-3/5.025

V1=2.149×10^5 Volts

Potential difference due to the second sphere is the same as the first, since both are identical

Total potential is V1 +V2

V=2.149E5+2.149E5

V=4.3E5Volts

Total potential at the middle due to the two sphere is 4.3×10^5Volts

d. The potential difference between the sphere at any point is equal to the potential difference found at c

Therefore the potential difference is

V=4.3×10^5Volts

4 0
3 years ago
Two electric charges are moved so that they are twice as far apart as they had originally been. Is the force they experience fro
Natasha_Volkova [10]

Answer:

No.

Explanation:

The force that two particle experience is inversely proportional to the sqare of the distance, this is:

F \  \alpha \  \frac{1}{D^{2}} for a distance D

If we move them so that D is doubled:

\frac{1}{2^{2}.D^{2}  }= \frac{1}{4} \eq  \frac{1}{.D^{2}  } \eq

Then the force they experience is one fourth of the original.

5 0
3 years ago
Complete the passage.
Sonbull [250]

Sound waves and some earthquake waves are <u><em>longitudinal </em></u>waves. Ocean, light, and other earthquake waves are <u><em>transverse</em></u> waves.

6 0
3 years ago
Read 2 more answers
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