Answer:
Explanation:
Two spheres 10m apart
Each charge on the sphere is 0.12mC= 0.12×10^-3C
Given that the diameter is
5cm=0.05m
Then, the radius is diameter / 2
r=d/2
r=0.05/2
r=0.025m
Potential is given as
V=kq/r
k=9×10^9Nm2/C2
a. Potential on each sphere surface.
They are going to have the same value since the sphere are identical
At the surface of the sphere,
r= 0.025m
V=kq/r
V=9E9×0.12E-3/0.025
V=4.32E7Volts
V=4.32×10^7Volts
b. The electric field at the surface of each sphere will be the same since the charge are identical,
So, Electric field is given as
E=kq/r^2
At the surface
E=9E9×0.12E-3/0.025^2
E=1.728×10^8N/C
c. The potential mid way between the two sphere
The potential difference due to the first sphere
The sphere are 10m apart then the distance mid way is 5m
Then, the radius of the sphere is 0.025m
Total distance from the center is 5.025m
Then,
V=kq/r
V1=9E9×0.12E-3/5.025
V1=2.149×10^5 Volts
Potential difference due to the second sphere is the same as the first, since both are identical
Total potential is V1 +V2
V=2.149E5+2.149E5
V=4.3E5Volts
Total potential at the middle due to the two sphere is 4.3×10^5Volts
d. The potential difference between the sphere at any point is equal to the potential difference found at c
Therefore the potential difference is
V=4.3×10^5Volts
