Answer:
The work done on the system can be accounted for by;
Both
and 
Explanation:
The speed of the crate = Constant
Therefore, the acceleration of the crate = 0 m/s²
The net force applied to the crate,
= 0
Therefore, the force of with which the crate is pulled = The force resisting the upward motion of the crate
However, we have;
The force resisting the upward motion of the crate = The weight of the crate + The frictional resistance of the ramp due to the surface contact between the ramp and the crate
The work done on the system = The energy to balance the resisting force = The weight of the crate × The height the crate is raised + The heat generated as internal energy to the system
The weight of the crate × The height the crate is raised = Gravitational Potential Energy = 
The heat generated as internal energy to the system = 
Therefore;
The work done on the system =
+
.
Answer:
The distance the plane covered while it was accelerating is 80,633.3 m
Explanation:
Given;
initial velocity of the plane, u = 90 m/s
acceleration of the plane, a = 1.5 m/s²
final velocity of the plane, v = 500 m/s
The distance covered by the plane is given as;
v² = u² + 2ad
where;
d is the distance covered by the plane;
500² = 90² + 2(1.5)d
500² - 90² = 3d
241900 = 3d
d = 241900 / 3
d = 80,633.3 m
Therefore, the distance the plane covered while it was accelerating is 80,633.3 m
It has a metallic luster
~ hope this helps ❤️