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pashok25 [27]
3 years ago
8

What is the function of an Erlenmeyer flask?

Chemistry
1 answer:
JulijaS [17]3 years ago
6 0
An Erlenmeyer flask is laboratory flask that has a conical shape and flat bottom with a tapered mouth. The Erlenmeyer flask is used for pouring, mixing and storing of chemicals in the laboratory. It was created by Emil Erlenmeyer in the 1860s.
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Heating 2.40 g of the oxide of metal X (molar mass of X = 55.9 g/mol) in carbon monoxide (CO) yields the pure metal and carbon d
Korolek [52]

Answer:The molecular formula of the oxide of metal be X_2O_3. The balanced equation for the reaction is given by:

X_2O_3+3CO\rightarrow 3CO_2+2X

Explanation:

Let the molecular formula of the oxide of metal be X_2O_y

X_2O_y+yCO\rightarrrow yCO_2+2X

Mass of metal product = 1.68 g

Moles of metal X =\frac{1.68 g}{55.9 g/mol}=0.03005 mol

1 mol of metal oxide produces 2 moles of metal X.

Then 0.03005 moles of metal X will be produced by:

\frac{1}{2}\times 0.03005 mol=0.01502 mol of metal oxide

Mass of 0.01502 mol of metal oxide = 2.40 g (given)

0.01502 mol\times (2\times 55.9 g/mol+y\times 16 g/mol)=2.40 g

y = 2.999 ≈ 3

The molecular formula of the oxide of metal be X_2O_3. The balanced equation for the reaction is given by:

X_2O_3+3CO\rightarrow 3CO_2+2X

8 0
3 years ago
The process of generating electricity from dams and nuclear power plants is very different, but some of the energy transformatio
Sindrei [870]

Answer:

yuh

Explanation:

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3 0
2 years ago
Bacteria consume other organisms for food, making them heterotrophs. True or False?​
11111nata11111 [884]

Answer:

I would say true!

Explanation:

5 0
3 years ago
Consider the reaction below for which K = 78.2 atm-1. A(g) + B(g) ↔ C(g) Assume that 0.386 mol C(g) is placed in the cylinder re
borishaifa [10]

Answer:

1.65 L

Explanation:

The equation for the reaction is given as:

                        A            +            B           ⇄        C

where;

numbers of moles = 0.386 mol C  (g)

Volume =  7.29 L

Molar concentration of C = \frac{0.386}{7.29}

= 0.053 M

                        A            +            B           ⇄        C

Initial               0                           0                      0.530    

Change          +x                          +x                       - x

Equilibrium      x                           x                      (0.0530 - x)

K = \frac{[C]}{[A][B]}

where

K is given as ; 78.2 atm-1.

So, we have:

78.2=\frac{[0.0530-x]}{[x][x]}

78.2= \frac{(0.0530-x)}{(x^2)}

78.2x^2= 0.0530-x

78.2x^2+x-0.0530=0  

Using quadratic formula;

\frac{-b+/-\sqrt{b^2-4ac} }{2a}

where; a = 78.2 ; b = 1 ; c= - 0.0530

= \frac{-b+\sqrt{b^2-4ac} }{2a}   or \frac{-b-\sqrt{b^2-4ac} }{2a}

= \frac{-(1)+\sqrt{(1)^2-4(78.2)(-0.0530)} }{2(78.2)}  or \frac{-(1)-\sqrt{(1)^2-4(78.2)(-0.0530)} }{2(78.2)}

= 0.0204  or -0.0332

Going by the positive value; we have:

x = 0.0204

[A] = 0.0204

[B] = 0.0204

[C] = 0.0530 - x

     = 0.0530 - 0.0204

     = 0.0326

Total number of moles at equilibrium = 0.0204 +  0.0204 + 0.0326

= 0.0734

Finally, we can calculate the volume of the cylinder at equilibrium using the ideal gas; PV =nRT

if we make V the subject of the formula; we have:

V = \frac{nRT}{P}

where;

P (pressure) = 1 atm

n (number of moles) = 0.0734 mole

R (rate constant) = 0.0821 L-atm/mol-K

T = 273.15 K  (fixed constant temperature )

V (volume) = ???

V=\frac{(0.0734*0.0821*273.15)}{(1.00)}

V = 1.64604

V ≅ 1.65 L

3 0
3 years ago
Can a molecule have polar bonds, but still be a no polar molecule?
My name is Ann [436]

<em><u>A molecule </u></em><em><u>can </u></em><em><u>possess polar bonds and still be nonpolar.</u></em>

I hope this helped. Have a nice day, make sure to take care of yourself. You're loved <3

5 0
4 years ago
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