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MaRussiya [10]
3 years ago
12

In each equation, label the acids, bases, and conjugate acid-base pairs. (Type your answer using the format [NO3]- for NO3-.)

Chemistry
1 answer:
Kamila [148]3 years ago
4 0

Answer:

a) O²⁻ + H₂O <-----> OH⁻ + OH⁻

Acid = H₂O

Base = O²⁻

Conjugate Acid = OH⁻

Conjugate Base = OH⁻

b) HClO₄ + H₂SO₄ <-----> ClO₄⁻ + H₃SO₄⁺

Acid = HClO₄

Base = H₂SO₄

Conjugate Acid = H₃SO₄⁺

Conjugate Base = ClO₄⁻

c) NH₃ + HNO₃ <--> NH4⁺ + NO₃⁻

Acid = HNO₃

Base = NH₃

Conjugate Acid = NH4⁺

Conjugate Base = NO₃⁻

Explanation:

- Acids are molecules or ions capable of donating a proton (H⁺).

- Bases are molecules or ions that readily accept the H⁺ from acids.

- Conjugate Acids, according to the Brønsted–Lowry acid–base theory, are chemical compounds formed after the reception of a proton (H⁺) from an acid by a base.

- Conjugate Bases, Brønsted–Lowry acid–base theory, are the leftovers from when acids donate their proton (H⁺).

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What volume of 0.500 M HNO3(aq) must completely react to neutralize 100.0 milliliters of 0.100 M KOH(aq)?
asambeis [7]
KOH+ HNO3--> KNO3+ H2O<span>
From this balanced equation, we know that 1 mol HNO3= 1 mol KOH (keep in mind this because it will be used later).

We also know that 0.100 M KOH aqueous solution (soln)= 0.100 mol KOH/ 1 L of KOH soln (this one is based on the definition of molarity).

First, we should find the mole of KOH:
100.0 mL KOH soln* (1 L KOH soln/ 1,000 mL KOH soln)* (0.100 mol KOH/ 1L KOH soln)= 1.00*10^(-2) mol KOH.

Now, let's find the volume of HNO3 soln:
1.00*10^(-2) mol KOH* (1 mol HNO3/ 1 mol KOH)* (1 L HNO3 soln/ 0.500 mol HNO3)* (1,000 mL HNO3 soln/ 1 L HNO3 soln)= 20.0 mL HNO3 soln.

The final answer is </span>(2) 20.0 mL.<span>

Also, this problem can also be done by using dimensional analysis. 

Hope this would help~ </span>
6 0
3 years ago
What drives this process
m_a_m_a [10]

Answer:

B

Explanation:

cool air never rises so not A

C would mean its getting warmer

and heat flows from warm to cool so not D

we are left with B

if my anwser helps please mark as brainliest.

8 0
3 years ago
Read 2 more answers
An 80.0g sample of an unknown metal is at an initial temperature of 55.5oC. Afer 540 J of energy is absorbed by the metal, the t
Lunna [17]

Answer:

Specific heat of metal = 0.26 j/g.°C

Explanation:

Given data:

Mass of sample = 80.0 g

Initial temperature = 55.5 °C

Final temperature = 81.75 °C

Amount of heat absorbed = 540 j

Specific heat of metal = ?

Solution:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT =  81.75 °C - 55.5 °C

ΔT =  26.25 °C

540 j = 80 g × c × 26.25 °C

540 j = 2100 g.°C× c

540 j / 2100 g.°C = c

c = 0.26 j/g.°C

7 0
2 years ago
What is the molarity of a solution that contains 148g NaOH in 4.00 L solution? a 0.925 M b 0.0253 M c 0.459 M d 1.363 M
Anton [14]

Answer:

M = 0,925

Explanation:

n= mass/Molecular Weight

n = 148g / 39,99 (g/mol)

n= 3,7mol

M= n/Volumen(L)

M= 3,7mol/4L

M=0,925

8 0
3 years ago
Why does pure iron not have many uses?
Brums [2.3K]
Because it is a pure substances <span />
4 0
3 years ago
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