1. Ur graph should have 2 vertical lines || , of equal height at mass 13 and 15.
2. One, because you have the mass, which in this case is 13 and the other 15, which has the same height. So it must be the isotope. By definition, an isotope has the same number of protons, but different number of neutrons.
3. to solve for fractional abundance, Let x = fraction of element: "I"-13
then fraction of "I"-15 must be 1-x
so you have: 13x + (15<span>)(1-x) = 13
solve for x.</span>
The gas sample consists of CH₄ and He.
Number of CH₄ moles - 4 g/ 16 g/mol = 0.25 mol
molar volume is where 1 mol of any gas occupies a volume of 22.4 L
Therefore 0.25 mol of CH₄ gas occupies a volume of 22.4 L/mol x 0.25 mol
Volume of methane - 5.6 L
Number of He moles - 2.00 g/ 4 g/mol = 0.5 mol
Volume occupied by He - 22.4 L /mol x 0.5 mol = 11.2 L
The total volume of the sample = 5.6 L + 11.2 L = 16.8 L
Hola aquí va la respuesta!
Se fomentó la inmigración europea porque la economía no era buena y vinieron a Paraguay para mejorar su situación.
Answer:
sp2
Explanation:
Orbital hybridization is defined as the changes in the orbitals of atoms when they pair with electrons of other atoms to form chemical bonds.
C atoms in C2Cl4 or tetrachloroethene have a total of three bond pairs, two with each chlorine atom and one with other carbon atom and zero lone pairs. Thus, C atoms in C2Cl4 is sp2 hybridized.
Hence, the correct answer is "sp2".
