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Lera25 [3.4K]
3 years ago
11

What part of Earth has a faster linear speed. *

Physics
1 answer:
lana66690 [7]3 years ago
3 0

Answer:

The equator has the greatest linear speed

(rotational, linear) speed varies.

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WINSTONCH [101]
I think its an echo?
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4 years ago
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Taking test, need physics help<br> ASAP please!
Anuta_ua [19.1K]

Answer:

im pretty sure its c the third answer i got that one right

Explanation:

your welcome :)

8 0
3 years ago
A common pickup for an electric guitar consists of a coil of wire around a small permanent magnet, as described in Figure 25.5.
Orlov [11]
Guitar pickups are tiny coils with magnets inside them and they work via  the principal of electromagnetic inductance. The metal strings vibrate within the magnetic field of the pickup which generates an electrical current. Since nylon is not a metal, it will not cause <span>fluctuations in that magnetic field. Hope this answer helps.</span>
6 0
3 years ago
A beam of electrons moving in the x-direction enters a region where a uniform 208-G magnetic field points in the y-direction. Th
GREYUIT [131]

Answer:

1.26\cdot 10^7 m/s

Explanation:

When a charged particle moves perpendicularly to a magnetic field, the force it experiences is:

F=qvB

where

q is the charge

v is its velocity

B is the strength of the magnetic field

Moreover, the force acts in a direction perpendicular to the motion of the charge, so it acts as a centripetal force; therefore we can write:

qvB=m\frac{v^2}{r}

where

m is the mass of the particle

r is the radius of the orbit of the particle

The equation can be re-arranges as

v=\frac{qBr}{m}

where in this problem we have:

q=1.6\cdot 10^{-19}C is the magnitude of the charge of the electron

B=208 G=208\cdot 10^{-4}T is the strength of the magnetic field

The beam penetrates 3.45 mm into the field region: therefore, this is the radius of the orbit,

r=3.45 mm = 3.45\cdot 10^{-3} m

m=9.11\cdot 10^{-31} kg is the mass of the electron

So, the electron's speed is

v=\frac{(1.6\cdot 10^{-19})(208\cdot 10^{-4})(3.45\cdot 10^{-3})}{9.11\cdot 10^{-31}}=1.26\cdot 10^7 m/s

6 0
3 years ago
An open pipe of length 0.58 m vibrates in the third harmonic with a frequency of 939Hz. What is the speed of sound through the a
vaieri [72.5K]

363 m/s is the speed of sound through the air in the pipe.

Answer: Option B

<u>Explanation:</u>

The formula used to calculate the wavelength given as below,

      Wavelength (\lambda)=\frac{\text { wave velocity }(v)}{\text { frequency }(f)}

      v=\lambda \times f   --------> eq. 1

In power system, harmonics define by positive integers of the fundamental frequency. So the third order harmonic is a multiple of the third fundamental frequency. Each harmonic creates an additional node and an opposite node, as well as an additional half wave within the string.

If the number of waves in the circuit is known, the comparison between standing wavelength and circuit length can be calculated algebraically. The general expression for this given as,

         L=\frac{n \lambda}{2}

For first harmonic, n =1

         L=\frac{\lambda}{2}

For second harmonic, n =2

         L=\frac{2 \lambda}{2}=\lambda

For third harmonic, n =3

         L=\frac{3 \lambda}{2}

         \lambda=\frac{2 L}{3}   -------> eq. 2

Here given f = 939 Hz, L = 0.58 m...And, substitute eq 2 in eq 1 and values, we get

   v=\frac{2 \times 0.58 \times 989}{3}=\frac{1089.24}{3}=363.08 \mathrm{m} / \mathrm{s}

3 0
3 years ago
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