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Marina CMI [18]
3 years ago
12

Suppose the flask is already at equilibrium but then the volume of the reaction flask is then reduced what will happen

Chemistry
1 answer:
sveta [45]3 years ago
8 0

1) Answer is: c) The reaction will proceed right.

Balanced chemical reaction: N₂(g) + 3H₂(g) ⇄ 2NH₃(g) ΔH = +92 kJ.

Reducing the volume of the system increase the partial pressures of the products and reactants.

With a pressure increase due to a decrease in volume, the side of the equilibrium with fewer moles is more favorable, there are 4 moles at the left side (three moles of hydrogen and one mole of nitrogen) and 2 moles (ammonia) at the right side of the reaction.

2) Answer is: d) The partial pressure of ammonia will increase.

This reaction is endothermic (enthalpy is higher than zero), which means that heat is added.

According to Le Chatelier's principle when the reaction is endothermic heat is included as a reactant and when the temperature increased, the heat of the system increase, so the system consume some of that heat by shifting the equilibrium to the right,  producing more ammonia.

You might be interested in
What gets reduced in an electrolytic cell made with nickel and copper electrodes?
jekas [21]

Answer:

D. Ni²⁺  

Explanation:

We know at once that the answer cannot be A or C, because Ni and Cu are already in their lowest oxidation states.

The correct answer must be either B or D.

An electrolytic cell is the opposite of a galvanic cell. In the former, the reaction proceeds spontaneously. In the latter, you must force the reaction to occur.  

One strategy to solve this problem is:

  1. Look up the standard reduction potentials for the half reaction·
  2. Figure out the spontaneous direction.
  3. Write the equation in the reverse direction.

1. Standard reduction potentials

                                E°/V

Cu²⁺ + 2e⁻ ⟶ Cu; 0.3419

Ni²⁺ + 2e⁻ ⟶ Ni;  -0.257

2. Galvanic Cell

We reverse the direction of the more negative half cell and add.

                                       <u>E°/V </u>

Ni ⟶ Ni²⁺ + 2e⁻;           0.257

<u>Cu²⁺ + 2e⁻ ⟶ Cu;      </u>   0.3419

Ni + Cu²⁺ ⟶ Cu + Ni²⁺; 0.599

This is the spontaneous direction.

Cu²⁺ is reduced to Cu.

3. Electrochemical cell

                                        <u>E°/V</u>

Ni²⁺ + 2e⁻ ⟶ Ni;           -0.257

<u>Cu ⟶ Cu²⁺ + 2e⁻;        </u> <u>-0.3419</u>

Cu + Ni²⁺ ⟶ Ni + Cu²⁺; -0.599

This is the non-spontaneous direction.

Ni²⁺ is reduced to Ni in the electrolytic cell.

8 0
3 years ago
Cl2 +2e- —&gt; 2Cl-
aleksandr82 [10.1K]

When two electrons are added to chlorine has, Cl2, each atom of Cl will receive one electron. Hence, the atoms becomes ions having a negative charge, Cl-

<h3>Ions</h3>

Ions are atoms or group of atoms possessing an electrical charge which may be positive or negative.

Negatively charged ions are formed when atoms accept or gain electrons. The negative charge is because there are more electrons than protons in the atom.

Negatively charged ions are usually formed by non-metals. For example, chlorine gas accepts two electrons to become 2 Cl-

Cl2 + 2e- ----> 2 Cl-

Therefore, when two electrons are added to chlorine has, Cl2, each atom of Cl will receive one electron. Hence, the atoms becomes ions having a negative charge, Cl-

Learn more about negative ions at: brainly.com/question/1046561

7 0
3 years ago
Hydrazine (N2H4) emits a large quantity of
azamat

Answer:

              1.75 moles of H₂O

Solution:

The Balance Chemical Equation is as follow,

                                   N₂H₄  +  O₂    →    N₂  +  2 H₂O

Step 1: Calculate the Limiting Reagent,

According to Balance equation,

             32.04 g (1 mol) N₂H₄ reacts with  =  32 g (1 mol) of O₂

So,

                   28 g of N₂H₄ will react with  =  X g of O₂

Solving for X,

                       X  =  (28 g × 32 g) ÷ 32.04 g

                       X  =  27.96 g of O₂

It means 29 g of N₂H₄ requires 47.96 g of O₂, while we are provided with 73 g of O₂ which is in excess. Therefore, N₂H₄ is the limiting reagent and will control the yield of products.

Step 2: Calculate moles of Water produced,

According to equation,

            32.04 g (1 mol) of N₂H₄ produces  =  2 moles of H₂O

So,

                        28 g of N₂H₄ will produce  =  X moles of H₂O

Solving for X,

                      X  =  (28 g × 2 mol) ÷ 32.04 g

                      X  =  1.75 moles of H₂O

5 0
4 years ago
Does anyone know how to make this picture more clear so I can see the numbers?
bogdanovich [222]

Answer:

i dont know how.

Explanation:

Have a great day?

6 0
3 years ago
Acetone (nail polish remover) has a density of 0.7857 g &gt;cm3.
Stella [2.4K]

If acetone has a density of 0.7857 \frac{g}{cm^{3} }  the mass in grams of point A is 22.4 g and the volume at point B is 8.32 mL.

<h3>What is acetone?</h3>

Acetone is known as a chemical substance that is usually found in the environment but can also be produced artificially. Acetone is a polar organic product that interacts very well with water molecules, generating dipole-dipole relationships.It is colorless with a distinctive smell and taste, we find it in products known as <u>cleaning and personal care products</u>, but we can also use it as a solvent for substances.

Also in the environment in <u>plants, trees and in volcano emissions or in forest fires</u>, it does not become <em>toxic</em> in low doses but if it is exposed to an individual in high doses it can become <em>fatal</em>.

In the statement we can find that acetone has a density of 0.7857 \frac{g}{cm^{3} }.

Therefore, we can confirm that if acetone has a density of 0.7857 \frac{g}{cm^{3} }  the mass in grams of point A is 22.4 g and the volume at point B is 8.32 mL.

To learn more about acetone visit: brainly.com/question/13334667?referrer=searchResults

#SPJ1

7 0
2 years ago
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