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Olenka [21]
3 years ago
12

What mass, in grams, of fluorine has (F2) is contained in a 10.3-liter tank at 29.8 degrees Celsius and 1.23 atmospheres? Show a

ll of the work used to solve this problem.
Chemistry
1 answer:
denis23 [38]3 years ago
8 0
PV = nRT
P is pressure, V is volume in L, n is number of moles, R is the gas constant, and T is temperature in K

(1.23 atm)(10.3 L) = (n)(.08206)(29.8 + 273)

n = .5 moles x 38 grams per mol F2 = 19.4 grams F2
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The scientific name for water is H2O because it contains:_________
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a

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Which of the following ways can the volume of a gas be changed, without changing its mass? Select all that apply.
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It can be spread into a smaller container

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Given the balanced reaction CH4 + 2O2 -> CO2 + 2H2O2 How many moles of oxygen are needed to completely react with 1 mole of C
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Answer: 2.0 moles of oxygen are needed to completely react with 1.0 mole of CH4 as shown in the balanced equation.

Explanation:

Stoichiometry is a fundamental tool and skill to determine the relative quantities that the chemicals react with. it determines the quantity of one substance to a quantity of another substance or substances. Stoichiometry is relating of one chemical substance to another using a balanced chemical reaction is called stoichiometry. Also, it is very important to predict what will occur and how much is produced through knowing the coefficients of moles of reactants and products.

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5 0
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3. Suppose you had titrated your vinegar sample with barium hydroxide instead of sodium hydroxide:
charle [14.2K]

Answer:

39.6 mL

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Step 1: Write the balanced neutralization reaction

Ba(OH)₂(aq) + 2 CH₃COOH(aq) ⟶ Ba(CH₃COO)₂(aq) + 2 H₂O(l)

Step 2: Calculate the moles corresponding to 2.78 g of CH₃COOH

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2.78 g × 1 mol/60.05 g = 0.0463 mol

Step 3: Calculate the moles of Ba(OH)₂ needed to react with 0.0463 moles of CH₃COOH

The molar ratio of Ba(OH)₂ to CH₃COOH is 1:2. The moles of Ba(OH)₂ needed are 1/2 × 0.0463 mol = 0.0232 mol.

Step 4: Calculate the volume of 0.586 M solution that contains 0.0232 moles of Ba(OH)₂

0.0232 mol × 1 L/0.586 mol = 0.0396 L = 39.6 mL

6 0
3 years ago
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