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Olenka [21]
2 years ago
12

What mass, in grams, of fluorine has (F2) is contained in a 10.3-liter tank at 29.8 degrees Celsius and 1.23 atmospheres? Show a

ll of the work used to solve this problem.
Chemistry
1 answer:
denis23 [38]2 years ago
8 0
PV = nRT
P is pressure, V is volume in L, n is number of moles, R is the gas constant, and T is temperature in K

(1.23 atm)(10.3 L) = (n)(.08206)(29.8 + 273)

n = .5 moles x 38 grams per mol F2 = 19.4 grams F2
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Did changing the concentration of the solid effect the change in temperature of the reaction?
wolverine [178]
I’m pretty sure it’s true
7 0
3 years ago
Read 2 more answers
What is the measured component of the orbital magnetic dipole moment of an electron with (a) ml = and (b) ml = ?
faust18 [17]

ANSWER:

What is the measured component of the orbital magnetic dipole moment of an electron with the values

(a)  ml=3

(b ) ml= −4

a) -278 x 10^{-23}J/T

b) 3.71 x 10^{-23}J/T

STEP-BY-STEP EXPLANATION:

a) ml= 3

Цorb,z = ml Цв = - (3) * (9.27e - 24) = -278 x 10^{-23}J/T

b) ml= 3

Цorb,z = ml Цв = - (-4) * (9.27e - 24) = 3.71 x 10^{-23}J/T

3 0
3 years ago
A student dropped a piece of nickel metal into a solution of HCl(aq). He observed the formation of gas bubbles and collected the
omeli [17]

Answer:

a. The student performed the splint test incorrectly. He should of observed a popping sound when the splint was placed in the test tube.

Explanation:

It is given that a student performed an experiment where he dropped a nickel metal in to HCl solution. He observed the reaction and performed a splint test in the test tube that is filled with a gas which is formed while Nickle is dropped into the solution of HCl.

But the experiment that the student performed was incorrect. He must have observed the popping sound when the splint was placed in the test tube.

When the splint was added to the gas splint flared up. The hydrogen gas pops out when exposed to the flame.

$Ni + HCl(aq) = NiCl + H_2$

Thus the correct option is (a).

5 0
3 years ago
if 5430 J of energy is used to heat 1.25 L of room temp. water (23.0 °C) whats the final temp of the water?
skelet666 [1.2K]

<span>We can use the heat equation,
Q = mcΔT </span>

 

<span>Where Q is the amount of energy transferred (J), m is the mass of the substance (kg), c is the specific heat (J g</span>⁻¹ °C⁻<span>¹) and ΔT is the temperature difference (°C).</span>


Density = mass / volume


The density of water = 0.997 g/mL

<span>Hence mass of 1.25 L (1250 mL) of water = 0.997 g/mL x 1250 mL</span>

<span>                                                                   = 1246.25 g</span>


Specific heat capacity of water = 4.186 J<span>/ g °C.</span>


Let's assume that there is no heat loss to the surrounding and the final temperature is T.

By applying the equation,

      5430 J = 1246.25 g x 4.186 J/ g °C x (T - 23) °C
(T - 23) °C = 5430 J / 1246.25 g x 4.186 J/ g °C
(T - 23) °C = 1.04 °C
               T = 1.04 °C + 23 °C
               T = 24.04 °C

Hence, the final temperature of the water is 24.04 °C.
4 0
3 years ago
A neutral atom of gold has the same number of electrons and what?
liraira [26]
Atomic mass!!! the electrons and atomic mass will always be the same most the time
6 0
3 years ago
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