Answer:
Following are the solution to this question:
Explanation:
Please find the complete question in the attachment.
Start of Laboratory
Dissolve 2-naphthol in the round bottom flask with ethanol.
Add pellets of sodium hydroxide and hot chips. Attach a condenser.
Heat for 20 minutes under reflux, until the put a burden dissolves.
After an additional hour, add 1-Bromobutane and reflux.
Pour the contents into a beaker with ice from a round bottom flask.
On a Bachner funnel, absorb the supernatant by vacuum filtration.
Utilizing cold water to rinse the material and dry that on the filter.
Ending of the Lab
Answer:
0.89kg
Explanation:
Q=mL L=specific latent heat
Q=energy required in J
m=mass in Kg
Q=mL
m=Q/L
m=2000000J/2.25 x 10^6 J kg-1
m=0.89kg
Answer:
Ag is the oxidizing agent
Explanation:
oxidizing agent in the following equation?
Al (s) + 3 Ag+ (aq) = Al+3 (aq) + 3 Ag (s)
Left side
Al = 1
Ag = 3
Right Side
Al = 1
Ag = 3
So it's balanced already good.
Define
oxidizing agent = An oxidizing agent is the substance that gains electrons and is reduced in a chemical reaction.
Al is the reducing agent.
Ag is the oxidizing agent
Answer:
The pressure in that cylinder = 1.12atm
Explanation:
We use general gas law to calculate it. General gas law is gotten by combining Boyle's law, Charles' law and Avogadro's law. Thus
P = nRT/V
Where n = number of moles
R = the gas constant
T is the Temperature, V is the volume and P is the pressure.
Given: T = 319K, V = 24L, R = 0.0821 L.atm/K.mol
The first step is to find n using
n = mass of O2/molar mass of O2
=32.7/32
=1.0219
Now, using P =nRT/V
P = 1.0219 ×0.0821×319÷24
Therefore P = 1.12atm
The number of atoms of K that are in 235 g of the compound is
2.57 x10^24 atoms
calculation
Step 1: find the moles of K2S
= moles = mass/molar mass
= 235 g/110 g/mol= 2.136 moles
Step 2: multiply 2.136 moles by no. of K atoms in K2S
= 2.136 x2 = 4.272 moles
Step 3: use the Avogadro's law to determine number of K atoms
that is according to Avogadro's law 1 mole = 6.02 x 10^23 atoms
4.272 moles= ? atoms
by cross multiplication
= (4.272 moles x 6.02 x10^23 atoms) / 1 mole = 2.57 x10^24 atoms
