Answer:
Molecules must collide with sufficient energy, known as the activation energy, so that chemical bonds can break. Molecules must collide with the proper orientation. A collision that meets these two criteria, and that results in a chemical reaction, is known as a successful collision or an effective collision.
Answer:
See explanation below
Explanation:
First, we need to understand that the monochlorination of an alkane like this one, involves substitution of one of the atoms of hydrogen of the molecule for an atom of chlorine.
This reaction takes place when the alkane reacts with Cl₂ in presence of light or heat.
When this happens, the first step involves the breaking of the double bond of the chlorine to form the ion Cl⁻.
The next step involves the substraction of the hydrogen of the molecule by the Chlorine. This will leave the alkane with a lone pair available for reaction.
The third step, the alkane with the lone pair of electron substract a chlorine for the beggining and form the mono chlorinated product.
The final step involves forming the remaining products with the remaining reagents there.
In the picture attached you have the mechanism and product for this reaction:
The most abundant of all of the isotopes of an element will be the one who's mass the mass of element is closest to. In this case, the mass of atomic carbon is closest to the mass of carbon-12.
Thus, Carbon-12 is the most abundant isotope.
solution:
the change in the boiling point is given as,
dTbp =2.30°c
elevation constant for the solvent is given by,
kb=0.512°c/m

= 4.49m
Answer:
+1, lose, 1, 4s, 4s and 3d
Explanation:
<em>An element with the valence electron configuration 4s¹ would form a monatomic ion with a charge of </em><em>+1</em><em>. In order to form this ion, the element will </em><em>lose</em><em> </em><em>1 </em><em>electron from the </em><em>4s </em><em>subshell.</em>
The corresponding oxidation reaction is:
K ⇒ K¹⁺ + 1 e⁻
[Ar] 4s¹ ⇒ [Ar]
<em>If an element with the valence configuration 4s² 3d⁶ loses 3 electrons, these electrons would be removed from the </em><em>4s and 3d</em><em> subshell(s).</em>
The corresponding oxidation reaction is:
Fe ⇒ Fe³⁺ + 3 e⁻
[Ar] 4s² 3d⁶ ⇒ [Ar] 4s⁰ 3d⁵