Some similarities between deserts and rainforests are that they support complex ecosystems, are powered by the sun/photosynthetic plants, are dangerous/mostly uninhabitable for humans, due to both conditions and wildlife, and are found mostly in the tropics
Answer is: a. Rubidium (Rb) is more reactive than strontium (Sr) because strontium atoms must lose more electrons.
The ionization energy (Ei) is the minimum amount of energy required to remove the valence electron, when element lose electrons, oxidation number of element grows (oxidation process).
Alkaline metals (group 1), in this example rubidium, have lowest ionizations energy and easy remove valence electrons (one electron), they are most reactive metals.
Earth alkaline metals (group 2), in this example strontium, have higher ionization energy than alkaline metals, because they have two valence electrons, they are less reactive.
Rubidium electron configuration: ₃₇Rb 1s²2s²2p⁶3s²3p⁶3d¹⁰4s²4p⁶5s¹; one valence electron is 5s¹ orbital.
Strontium electron configuration: ₃₈Sr 1s²2s²2p⁶3s²3p⁶3d¹⁰4s²4p⁶5s²; two valence electrons is 5s² orbital.
Answer:
Final temperature = 
Explanation:
Given that,
Heat added, Q = 250 J
Mass, m = 30 g
Initial temperature, T₁ = 22°C
The Specific heat of Cu= 0.387 J/g °C
We know that, heat added due to the change in temperature is given by :
Put all the values,
So, the final temperature is equal to .
Answer:
1.126 M
Explanation:
From the question given, we obtained the following:
Mass of LiBr = 98g
Volume = 1 L
Molarity of LiBr =?
Next, we'll determine the number of mole of LiBr. This is illustrated below:
Molar Mass of LiBr = 7 + 80 = 87g/mol
Mass of LiBr = 98g
Number of mole = Mass/Molar Mass
Number of mole of LiBr = 98/87
Number of mole of LiBr = 1.126 mole
Now, we can calculate the molarity of LiBr. This is illustrated below:
Molarity is defined as mole per unit litre of the solution. Mathematically, it is represented as:
Molarity = mole /Volume
Mole of LiBr = 1.126 mole
Volume = 1 L
Molarity of LiBr =?
Molarity of LiBr = 1.126 mole /1 L
Molarity of LiBr = 1.126 M
Heat energy released : 167.2 kJ
<h3>Further explanation</h3>
Heat can be calculated using the formula:
Q = mc∆T
Q = heat, J
m = mass, g
c = specific heat, joules / g ° C
∆T = temperature difference, ° C / K
m = 2000 g
c = 4.18 J/ g ° C
∆t = 20 ° C
