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Elanso [62]
3 years ago
14

The product of a combination reaction is Ca(OH)2. If one of the reactants is H20 wat is the other reactant

Chemistry
2 answers:
Alexeev081 [22]3 years ago
8 0

Answer:

H2O+CaO=Ca(OH)2.

SOVA2 [1]3 years ago
4 0
CaO. Both the hydrogens have been used in the water, along with one oxygen, only heaving the Ca and one remaining Oxygen.
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What do blizzards consist of? (Select all that apply)
Maru [420]

Answer:

Heavy Snowfall

High Winds

Extremely Low Temperatures

Reasoning:

Lots of snow, kinda self explanatory

high winds are needed to carry the snow that fast

its has to be below freezing for snow to even form

7 0
2 years ago
How many moles of AlCl3 are formed by 1.53 moles of CuCl2?
jolli1 [7]

Answer:

1.02 moles of AlCl3

Explanation:

Consider the balanced reaction equation shown below;

2Al(s) + 3CuCl2(aq) -------> 2AlCl3 (aq) + 3Cu(s)

This is the balanced reaction equation for the reaction going on above. Recall that the first step in solving any problem is to accurately put down the chemical reaction equation. This balanced reaction equation always serves a reliable guide in solving the problem at hand.

Given that;

3 moles of CuCl2 yields 2 moles of AlCl3

1.53 moles of CuCl2 yields 1.53 × 2 / 3 =1.02 moles of AlCl3

5 0
2 years ago
Some students were investigating the
nordsb [41]

Answer:

I am a grade six student but I am very interested in chemistry

Explanation:

I sorry but this is NOT chemistry

5 0
3 years ago
Read 2 more answers
Calcium oxide is a basic oxide.Explain, using a chemical equation, why calcium oxide is basic.​
zlopas [31]

Answer:

Explanation:Calcium oxide (CaO), commonly known as quicklime or burnt lime, is a widely used chemical ... Chemical formula. CaO ... Both it and a chemical derivative (calcium hydroxide, of which quicklime is the base anhydride) are important commodity ... The major use of quicklime is in the basic oxygen steelmaking (BOS) process.

5 0
3 years ago
A hypothetical element has an atomic weight of 48.68 amu. It consists of three isotopes having masses of 47.00 amu, 48.00 amu, a
Morgarella [4.7K]

Answer : The percent abundance of the heaviest isotope is, 78 %

Explanation :

Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.

Formula used to calculate average atomic mass follows:

\text{Average atomic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i

As we are given that,

Average atomic mass = 48.68 amu

Mass of heaviest-weight isotope = 49.00 amu

Let the percentage abundance of heaviest-weight isotope = x %

Fractional abundance of heaviest-weight isotope = \frac{x}{100}

Mass of lightest-weight isotope = 47.00 amu

Percentage abundance of lightest-weight isotope = 10 %

Fractional abundance of lightest-weight isotope = \frac{10}{100}

Mass of middle-weight isotope = 48.00 amu

Percentage abundance of middle-weight isotope = [100 - (x + 10)] %  = (90 - x) %

Fractional abundance of middle-weight isotope = \frac{(90-x)}{100}

Now put all the given values in above formula, we get:

48.68=[(47.0\times \frac{10}{100})+(48.0\times \frac{(90-x)}{100})+(49.0\times \frac{x}{100})]

x=78\%

Therefore, the percent abundance of the heaviest isotope is, 78 %

5 0
3 years ago
Read 2 more answers
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