Question

A plug-in transformer supplies 9 V to a video game system. (a) How many turns are in its secondary coil, if its input voltage is 111 V and the primary coil has 340 turns? g

Answer 1

28 turns

Explanation:

The transformer equation given as

$\frac{V_{s} }{V_{p} } =\frac{N_{s} }{N_{p} }$

Here,${N_{s} }, {N_{p} }$ are the number of loops in the primary and secondary coil respectively and ${V_{s} },{V_{p} }$  are the output and input voltages.

Substitute the given values, we get

$\frac{9.00V}{111.00V} =\frac{N_{s} }{340}$

$N_{s} =\frac{9\times340 }{111}$

$N_{s}=27.57 =28$

Thus, the turns in secondary coil are 28.  

Answer 2

Answer:

The number of turns in the secondary coil is 28.

Explanation:

Given that,

Input voltage given to the transformer, $V_p=111\ V$

Output voltage supplied to the video game, $V_s=9\ V$

Number of turns in the primary coil, $N_p=340$

We need to find the number of turns in its secondary coil. We know that the transformer equation is given by :

$\dfrac{V_s}{V_p}=\dfrac{N_s}{N_p}\\\\N_s=\dfrac{V_s}{V_p}\times N_p\\\\N_s=\dfrac{9}{111}\times 340\\\\N_s=27.56$

or

$N_s=28$

So, the number of turns in the secondary coil is 28.