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Fynjy0 [20]
4 years ago
6

Offenders who are under house arrest may not leave their residences for any reason

Physics
1 answer:
WITCHER [35]4 years ago
6 0
This is false. I hope this helps.
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A charged particle is surrounded by an electric field and a magnetic field
zlopas [31]

Answer:

yeah

Explanation:

electric fields help the charged particles interact

and isn't magnetic field the same as electric field.

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3 years ago
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Who is the Prime Minister of India​
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MR NARENDRA MODI

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Why is physics an important part of history
tigry1 [53]

Answer:

History and physics are intertwined through all the revolutionary thinkers, scientists, and people who studied these ideas. For example, many historical thinkers such as Isaac Newton and Galileo Galilei not only had revolutionary ideas, but they also changed life forever as the people knew it. It shocked the people and taught them new things, and upset the church.

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4 years ago
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A spring of spring constant k=8.25N/m is displaced from equilibrium by a distance of 0.150m. What is the stored energy in the fo
inysia [295]

Answer:

0.0928J

Explanation:

the pulling force of spring F=-kx

where x is the displacement from equilibrium position.

energy stored:

\int\limits^x_0 {-F} \, dx \\=\int\limits^x_0 {kx} \, dx \\\\=\frac{kx^{2} }{2}

*** Its fine if you know nothing about calculus. Just apply the equation

    U=\frac{kx^{2} }{2}

  where U is the potential energy of the spring***

  put x=0.150, U=\frac{8.25}{2}×0.150^{2} = 0.0928J (corr. to 3 sig. fig.)

4 0
3 years ago
How long will it take a car to go from a complete stop to 44 km/hr if they are accelerating at 5 km/hr?
Aleonysh [2.5K]

<u>Solu</u><u>tion</u><u> </u><u>:</u><u>-</u>

Given that ,

  • Initial Velocity of car = 44km / hr.
  • Final Velocity of car = 0km / hr.
  • Acceleration = -5km/hr².

To Find :

  • Time taken to stop the car .

So , here use first equⁿ of motion which is ,

\boxed{\red{\bf\dag v = u + at }}

where ,

  • v is final Velocity.
  • u is Initial velocity.
  • a is acceleration.
  • t is time taken.

Now , substituting the respective values ,

\tt:\implies v=u+at

\tt:\implies 0 = 44 + (-5)t

\tt:\implies -44 = -5t

\tt:\implies t=\dfrac{44}{5}

\underline{\boxed{\red{\tt \longmapsto Time\:\:=\:\:8.8hrs.}}}

\boxed{\green{\bf\pink{\dag} Hence\:time\:taken\:to\:stop\:the\:car\:is\:8.8hrs.}}

6 0
3 years ago
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