Answer:

Explanation:
We could use conversation of energy. Total distance the stone will cover will be

the Final velocity will be

Answer:

Explanation:
given,
op-amp circuit with a gain of = (Av₁) = 96 V/V
Band width = (Bw₁) = 8 kHz
Required bandwidth(Bw₂) = 32 kHz
Highest gain available =(Av₂) = ?
For the given system Bandwidth product is constant
Av₁ Bw₁ = Av₂ Bw₂
96 x 8 = Av₂ x 32


the highest gain available under these conditions 
C, they didn't know any better
Answer:
6.88 mA
Explanation:
Given:
Resistance, R = 594 Ω
Capacitance = 1.3 μF
emf, V = 6.53 V
Time, t = 1 time constant
Now,
The initial current, I₀ = 
or
I₀ = 
or
I₀ = 0.0109 A
also,
I = ![I_0[1-e^{-\frac{t}{\tau}}]](https://tex.z-dn.net/?f=I_0%5B1-e%5E%7B-%5Cfrac%7Bt%7D%7B%5Ctau%7D%7D%5D)
here,
τ = time constant
e = 2.717
on substituting the respective values, we get
I = ![0.0109[1-e^{-\frac{\tau}{\tau}}]](https://tex.z-dn.net/?f=0.0109%5B1-e%5E%7B-%5Cfrac%7B%5Ctau%7D%7B%5Ctau%7D%7D%5D)
or
I =
or
I = 0.00688 A
or
I = 6.88 mA
Answer:the resistance decrease
Explanation: