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DedPeter [7]
3 years ago
10

Question1 of 10

Physics
2 answers:
kakasveta [241]3 years ago
8 0
I believe the answer is B because they are interfering and combining into something bigger and brighter
olga_2 [115]3 years ago
5 0

Answer:

OC

Explanation:

because when light strikes soap bubbles it splits to form different colors

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Examine the circuit. Pretend you are an electron flowing through this circuit and you are with a group of other electrons. Sudde
melamori03 [73]

You knew that this question is ridiculously easy.  So, just to
make it harder, you decided not to let us see the picture, so
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kind is a series circuit, and that one has no forks in the road.
7 0
3 years ago
Read 2 more answers
A bus travels east for 3 km, then north for 4 km. What is its final displacement?
ikadub [295]
5 km northeast. Left and up would make northeast

8 0
3 years ago
What will one see during an annular eclipse?
KATRIN_1 [288]

Partial eclipse, Annular eclipse, Total Eclipse and Hybrid Eclipse are the four different types of the eclipses. When the Sun and Moon are exactly in line with the Earth, the annular eclipse occurs. The new moon is invisible from the earth and it is silhouetted against the sun, this can only be seen in annular eclipse. Annular word means ring shaped, we can see a dark ring of fire in annular eclipse. It has five different stages that are first contact, second contact, maximum eclipse, third contact and 4th contact.

7 0
3 years ago
When a carpenter shuts off his circular saw, the 10.0 inch diameter blade slows from 4250 rpm to 0.00 in 4.00 s. (a) What is the
MaRussiya [10]

Answer:

(a) \alpha=-111.26rad/s

(b) s=4450.6in

(c) 8.66in

Explanation:

First change the units of the velocity, using these equivalents 1rev=2\pi rad and 1 min =60s

4250rpm(\frac{2\pi rad}{1rev})(\frac{1 min}{60 s} )=445.06rad/s

The angular acceleration \alpha the time rate of change of the angular speed \omega according to:

\alpha=\frac{\Delta \omega}{\Delta t}

\Delta  \omega=\omega_i-\omega_f

Where \omega_i is the original velocity, in the case the velocity before starting the deceleration, and \omega_f is the final velocity, equal to zero because it has stopped.

\alpha=\frac{\Delta \omega}{\Delta t} =\frac{\omega_i-\omega_f}{4}\frac{0-445.06}{4} =\frac{-445.06}{4} =-111.26rad/s

b) To find the distance traveled in radians use the formula:

\theta = \omega_i t + \frac{1}{2} \alpha t^2

\theta = 445.06 (4) + \frac{1}{2}(-111.26) (4)^2=1780.24-890.12=890.12rad

To change this result to inches, solve the angular displacement \theta for the distance traveled s (r is the radius).

\theta=\frac{s}{r} \\s=\theta r

s=890.12(5)=4450.6in

c) The displacement is the difference between the original position and the final. But in every complete rotation of the rim, the point returns to its original position. so is needed to know how many rotations did the point in the 890.16 rad of distant traveled:

\frac{890.12}{2\pi}=141.6667

The real difference is in the 0.6667 (or 2/3) of the rotation. To find the distance  between these positions imagine a triangle formed with the center of the blade (point C), the initial position (point A) and the final position (point B). The angle \gamma=\frac{2\pi}{3}=\frac{360^o}{3}=120 is between the two sides known. Using the theorem of the cosine we can find the missing side of the the triangle(which  is also the net displacement):

c^2=a^2+b^2-2abcos(\gamma)

c^2=5^2+5^2-2(5)(5)cos(\frac{2\pi}{3} )\\c^2=25+25+25\\c^2=75\\c=5\sqrt{3}=8.66in

4 0
3 years ago
What kind of light would be the best to use to look inside a cold dark cloud and see the warm stars forming inside?
lys-0071 [83]
<h2>Answer: Infrared light</h2>

A dark nebula is a cloud of dust and cold gas, which does not emit visible light and hides the stars it contains.

These types of nebulae are composed mainly of the hydrogen they obtain from nearby stars, which is their fuel.

It is using infrared light that we can "observe" and analyze in detail what happens in the inner parts of these nebulae.

7 0
2 years ago
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