Answer:
Average speed = 1.2 m/s
Average velocity = 0.4 m/s
Explanation:
Average speed = total distance/total time
Average speed = (40 + 20)/(40 + 10)
Average speed = 60/50
Average speed = 1.2 m/s
Average velocity = displacement/time
Now, she ran 40 m south and ran 20 m back north which is in the direction of where she began the journey.
Thus;
Displacement = 40 - 20 = 20 m
Average velocity = 20/50 = 0.4 m/s
How much heat<span> is </span>required<span> to </span>heat 0.1 g<span> of </span>∆hvap<span> =</span>2260 j/g ∆h<span> =</span>340j/g fus iceat−30 ctosteamat 100c?use<span> the </span>approximate values<span>?</span>
That’s kinda messed up ⬆️
Answer:
speed of the car before the brakes were apply is 12.35 m/s
Explanation:
given data
accident measured distance = 73 feet = 22.25 m
to find out
speed of car before the brakes
solution
we consider here coefficient of kinetic friction between the road and the tires is 0.35
and we take speed of the car just before skidding = u
and final speed of car will be v = 0
now we apply here work energy theorem
so
0.5 mv² - 0.5 mu² = (- coefficient of kinetic friction × mass × g ) distance .......1
0.5( v² -u² ) = (- coefficient of kinetic friction × g ) distance
put here value and we get
0.5 ( 0 - u² ) = (- 0.35 × 9.8 ) 22.25
solve it we get
u = 12.35
speed of the car before the brakes were apply is 12.35 m/s
