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2 years ago

Compare the fractions. Use <, =, or >. 1/3 ? 4/6

Mathematics

1 answer:

zloy xaker [14]2 years ago

8 0

1/3 vs 4/6

get a common denominator of 6

1/3 * 2/2 vs 4/6

2/6 vs 4/6

2/6 < 4/6

so 1/3 < 4/6

Answer <

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For every pound a company spends on advertising, it spends 43 pence

irakobra [83]

Answer:

20:9

Step-by-step explanation:

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2 years ago

The timekeeper for a particular mile race uses a stopwatch to determine the finishing times of the racers. He then calculates th

insens350 [35]

Answer:

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Step-by-step explanation:

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So the Accurate mean is 5 minutes

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3 years ago

If a student didn’t understand proportional relationships, how would you explain it to them?

kirill [66]

Answer:

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2 years ago

Read 2 more answers

Hello i need help solving the following inequality X (X + 3) ⩽ X (2X + 5) thanks

igor_vitrenko [27]

Answer:

-2 ⩽ x

Step-by-step explanation:

x(x + 3) ⩽ x (2x + 5) divide both sides of tge inequality with x

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3 0

3 years ago

In the equation (x^2+y)^5, what is the coefficient of the term x^4y^3? what is the coefficient of the same term in the expansion

lys-0071 [83]

$\displaystyle
(x+y)^n=\sum_{k=0}^n\binom{n}{k}x^{n-k}y^k$

-------------------------------------------------------------

$\displaystyle
(x^2+y)^n=\sum_{k=0}^n\binom{n}{k}x^{2n-2k}y^k\\
n=5\\
k=3\\\\\binom{5}{3}=\dfrac{5!}{3!2!}=\dfrac{4\cdor5}{2}=10$

It's 10.

----------------------------------------------------

$\displaystyle
(3x^2+y)^n=\sum_{k=0}^n\binom{n}{k}(3x)^{2n-2k}y^k=\sum_{k=0}^n\binom{n}{k}\cdot 3^{2n-2k}\cdot x^{2n-2k}y^k\\\\
n=5\\
k=4\\\\
\binom{5}{3}\cdot3^{2\cdot5-2\cdot4}=10\cdot3^{2}=10\cdot9=90$

It's 90

6 0

3 years ago