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-Dominant- [34]
3 years ago
15

What's the word called part of an experiment that changes to observe an outcome?

Chemistry
1 answer:
Fiesta28 [93]3 years ago
8 0
That is called the<u> variable</u> because it varies/changes in the experiment,

it's like x in algebra (with more than one placeholder), if it changes, it normally gives you a different result
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What is the acceleration object velocity of +25m/s to rest in 5.0 s
Irina-Kira [14]

The average acceleration is -5.0 m·s⁻².

The formula for acceleration (<em>a</em>) is

a = \frac{v_{f}- v_{i}}{t}

v_{f} = 25 m·s⁻¹;  v_{i} = 0; t = 5.0 s

∴ a = \frac{0-25}{5.0} = -5.0 m·s⁻²

The negative sign tells you that the object is <em>slowing down</em>, i.e., it is <em>decelerating</em>.


4 0
4 years ago
What are 3 household examples of bases? &amp;<br> What are 3 characteristics of Bases
Digiron [165]
Bleach
glass cleaner
dish-detergent
A base removes hydrogen ions from a solution
A base decreases the hydrogen ion concentration in a solution
on a ph scale something is basic if it's measured 8-14

4 0
3 years ago
A piece of high-density Styrofoam measuring 24.0 cm by 36.0 cm by 5.0 cm floats when placed in a tub of water. When a 1.5 kg boo
zheka24 [161]

Explanation:

The given data is as follows.

         Width of Styrofoam = 24.0 cm

          Length of Styrofoam = 36.0 cm

          Height of Styrofoam = 5.0 cm

Therefore, volume of the Styrofoam will be calculated as follows.

                  Volume = length × width × height

                                =  (36.0 × 24.0 × 5.0) cm^{3}

                                 = 4320 cm^{3}

or,                             = 4.32 \times 10^{3} cm^{3}

As Styrofoam partially sinks at 3.0 cm and total height of Styrofoam is 5.0 cm. Hence, height of Styrofoam above the water is (5.0 - 3 cm) = 2 cm.

So, volume of water displaced is as follows.

          24.0 cm × 36.0 cm × 2.0 cm

         = 1.73 \times 10^{3} cm^{3}

Hence, mass of displaced water is as follows.

                 mass = density × volume

                           = 1.00 g/cm^{3} \times 1.73 \times 10^{3} cm^{3}

                           = 1.73 \times 10^{3} g

Since, book is placed on the Styrofoam. Therefore, mass of water displaced is also equal to the following.

             Mass of water displaced = mass of book + mass of Styrofoam

                  1.73 \times 10^{3} g = 1500 g + mass of Styrofoam

                   (1730 - 1500) g = mass of Styrofoam

                   mass of Styrofoam = 230 g

Therefore, calculate the density of Styrofoam as follows.

                   Density = \frac{mass}{volume}  

                                 = \frac{230}{4.32 \times 10^{3} cm^{3}}

                                 = 53.24 \times 10^{-3} g cm^{-3}

Thus, we can conclude that the density of Styrofoam is 53.24 \times 10^{-3} g cm^{-3}.

4 0
3 years ago
When stress is added to plates they can diverge, converge, or slip past one another True or False
zmey [24]
The answer is True i believe
5 0
3 years ago
What element is a non-metal.<br> A. Mg<br> B. Rb<br> C. Li<br> D. Br<br> E. Si
Goryan [66]

Answer:

D.) Br

Explanation:

I don’t really have an explanation.

I hope this helps!

4 0
3 years ago
Read 2 more answers
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