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3 years ago

What's the word called part of an experiment that changes to observe an outcome?

1 answer:

8 0

That is called the variable because it varies/changes in the experiment,

it's like x in algebra (with more than one placeholder), if it changes, it normally gives you a different result

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PLEASE HELP MEEEEE

igor_vitrenko [27]

Answer:

hey there! it gains an electron and has an octet in its inner shell it loses an electron and has an octet in the next lowest energy level it gains an electron and has an octet in the lowest energy level it gains an electron and has an octet in its outer shell

HAVE A GRET DAY! ;D

Explanation:

tbh idk if im 100% sure if im right but i hope i am :)

8 0

2 years ago

Read 2 more answers

The molecular weight of table salt, NaCl, is 58.5 g/mol. A tablespoon of salt weighs 6.37 grams. Calculate the number of moles o

cestrela7 [59]

Answer:

The number of moles of salt in one tablespoon is = 0.11 mole

Grams cancel each other.

Explanation:

Moles : It is the unit of quantity . It is the mass of the substance present in exactly 12g of C-12.

$moles=\frac{given\ mass}{Molar\ mass}$

Moles Calculation:

Given mass = 6.37 gram

Molar mass = 58.5 g/mol

$moles=\frac{6.37}{58.5}$

= 0.1088

= 0.11 mole

Units calculation

$moles=\frac{given\ mass}{Molar\ mass}$

$moles=\frac{g}{g/mole}$

$moles=\frac{g}{g}\times mole$

g ang g cancels each other

moles = moles

Hence unit = gram (g ) cancel each other.

3 0

3 years ago

Read 2 more answers

A gas under a pressure of 74 mmHg and at a temperature of 75°C occupies a 500.0-L container. How many moles of gas are in the co

Leona [35]

Answer : The number of moles of gas present in container are 1.697 mole.

Explanation :

Using ideal gas equation,

$PV=nRT$

where,

P = pressure of gas = 74 mmHg = 0.097 atm

conversion used : (1 atm = 760 mmHg)

V = volume of gas = 500.0 L

T = temperature of gas = $75^oC=75+273=348K$

n = number of moles of gas = ?

R = gas constant = 0.0821 L.atm/mole.K

Now put all the given values in the ideal gas equation, we get the number of moles of gas in the container.

$(0.097atm)\times (500.0L)=n\times (0.0821L.atm/mole.K)\times (348K)$

$n=1.697mole$

Therefore, the number of moles of gas present in container are 1.697 mole.

4 0

2 years ago

8CO + 17H2 → C8H18 + 8H2O

nekit [7.7K]

$\frac{6.50mole CO}{1} \frac{17mole H2}{8mole CO}\frac{2 gram H2}{1mole H2} =27.625$

3 sig figs= 27.6

4 0

2 years ago

to find the mass of 3.2 moles of calcium for carbonate which of the following is used to calculate the amount

natka813 [3]

I believe it to be g/mol of Calcium carbonate
because to finde mass...u must have grams(g) as units....
it is the only one that have g as units

as for the first answer the avogadros number gives u the number of atoms in one mole of calcium carbonate....
the second one is based on ... At s.t.p one mole of gas occupies 22.4 dm³⇒to find volume

6 0

2 years ago