The physical properties of matter are going to be appearance,texture, density. hope that helped
Answer:
1. 0.74mol
2. 0.42mol
3. 2.125mol
4. 0.301mol
5. 4.52 × 10^23 particles
Explanation:
Number of moles (n) in a substance can be found using the formula:
mole (n) = mass/molar mass
Using this formula, the following moles are calculated:
1. Molar of Na = 23g/mol
mole = 17/23
mole = 0.74mol
2. Molar mass of Na2SO4 = 23(2) + 32 + 16(4)
= 46 + 32 + 64
= 142g/mol
Mole = 60/142
mole = 0.42mol
3. Molar mass of CO2 = 12 + 16(2)
= 12 + 32
= 44g/mol
mole = 93.5/44
mole = 2.125mol
4. Molar mass of sodium nitrate (NaNO3) = 23 + 14 + 16(3)
= 23 + 14 + 48
= 85g/mol
mole = 25.6/85
mole = 0.301mol
5. Number of particles in one mole of a substance is 6.022 × 10^23 particles. Hence, in 0.75mol of calcium hydroxide (Ca(OH)2, there will be;
0.75mol × 6.02 × 10^23
= 4.515 × 10^23
= 4.52 × 10^23 particles
Answer: a metal and a nonmental and a mental and a polyatomic anion :)
Explanation: i prayed ~.~
Answer:
295.96 K ( = 22.81 degrees C)
Explanation:
PV = n RT R = .082057 L-Atm / (K-Mol) n = 3.5 P = 1 atm V = 85 liters
(1)(85) = 3.5 (.082057)(T)
solve for T = 295.96 K
Answer:
2,53x10⁻³ moles of NaOH
Explanation:
The reactions of a diprotic acid with NaOH are:
H₂X + NaOH → HX⁻ + H₂O + Na⁺
HX⁻ + NaOH → X²⁻ + H₂O + Na⁺
Where the complete first reaction gives the first equivalence point and the complete second reaction gives the second equivalence point.
The total volume spent of NaOH to reach the second equivalence point is:
7,00mL + 14,07mL = 21,07 mL = <em>0,02107L</em>
As molar concentration of NaOH is 0,120M, the moles used to reach the second equivalence point are:
0,02107L×(0,120mol/L) = <em>2,53x10⁻³ moles of NaOH</em>
I hope it helps!
