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Y_Kistochka [10]
2 years ago
14

What do organisms have based on their functions?

Chemistry
1 answer:
mote1985 [20]2 years ago
6 0
Unicellular organisms, cells perform all the basic actions and functions required for living like nutrition, respiration, reproduction etc.

In multicellular organisms, cells divide their tasks on the basis of "DIVISION OF LABOUR" to specialize in certain functions besides respiration etc. Like conduction in neurons, excitation in muscles, RBC production by bone marrow etc.
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Someone plss help me!!!
NikAS [45]

Answer:

d. Cl2

sorry if I'm wrong

Cl2, as shown in the picture should have electrons in both the atoms but, in the question, the electrons are only in one of the atoms.

hope it helps :)

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2 years ago
Each molecule of table sugar, C12H22O11, contains
Delicious77 [7]
D, because C12 means there's 12 atoms of carbon. 
3 0
3 years ago
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A solution has a pH of 11.8. What is the pOH?
amid [387]

Answer:

pOH is 2.2

Explanation:

The pH scale goes from 0 to 14. As such, the pH and the pOH add up to 14. Subtract your pH from 14 to get your answer.

14 - 11.8 = 2.2

5 0
2 years ago
I BEG YOU I NEED IT TILL 12 PLEASE ILL GIVE THE BRAINLEST AND HEARTS AND POINTS HELP PLEASEEEE !!!!!!!!!!!!!!!!!!!!!!!!!
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UHHHHHHHH IDRK TRY THE LINK ABOVE
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Helpppp pleaseee ill give brainliest
Studentka2010 [4]

Answer:

The answers are in the explanation.

Explanation:

The energy required to convert 10g of ice at -10°C to water vapor at 120°C is obtained per stages as follows:

Increasing temperature of ice from -10°C - 0°C:

Q = S*ΔT*m

Q is energy, S specific heat of ice = 2.06J/g°C, ΔT is change in temperature = 0°C - -10°C = 10°C and m is mass of ice = 10g

Q = 2.06J/g°C*10°C*10g

Q = 206J

Change from solid to liquid:

The heat of fusion of water is 333.55J/g. That means 1g of ice requires 333.55J to be converted in liquid. 10g requires:

Q = 333.55J/g*10g

Q = 3335.5J

Increasing temperature of liquid water from 0°C - 100°C:

Q = S*ΔT*m

Q is energy, S specific heat of ice = 4.18J/g°C, ΔT is change in temperature = 100°C - 0°C = 100°C and m is mass of water = 10g

Q = 4.18J/g°C*100°C*10g

Q = 4180J

Change from liquid to gas:

The heat of vaporization of water is 2260J/g. That means 1g of liquid water requires 2260J to be converted in gas. 10g requires:

Q = 2260J/g*10g

Q = 22600J

Increasing temperature of gas water from 100°C - 120°C:

Q = S*ΔT*m

Q is energy, S specific heat of gaseous water = 1.87J/g°C, ΔT is change in temperature = 20°C and m is mass of water = 10g

Q = 1.87J/g°C*20°C*10g

Q = 374J

Total Energy:

206J + 3335.5 J + 4180J + 22600J + 374J =

30695.5J =

30.7kJ

5 0
2 years ago
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