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3 years ago

Which one of the following reactions is NOT balanced?

Chemistry

1 answer:

Korolek [52]3 years ago

6 0

Answer:

co+ o2+ 2co2 is not balanced reaction

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A 76.0-gram piece of metal at 96.0 °C is placed in 120.0 g of water in a calorimeter at 24.5 °C. The final temperature in the ca

Phoenix [80]

The specific heat capacity of the metal given the data from the question is 0.66 J/gºC

<h3>Data obtained from the question</h3>

Mass of metal (M) = 76 g
Temperature of metal (T) = 96 °C
Mass of water (Mᵥᵥ) = 120 g
Temperature of water (Tᵥᵥ) = 24.5 °C
Equilibrium temperature (Tₑ) = 31 °C
Specific heat capacity of the water (Cᵥᵥ) = 4.184 J/gºC
Specific heat capacity of metal (C) =?

<h3>How to determine the specific heat capacity of the metal</h3>

The specific heat capacity of the sample of the metal can be obtained as follow:

Heat loss = Heat gain

MC(M –Tₑ) = MᵥᵥCᵥᵥ(Tₑ – Tᵥᵥ)

76 × C × (96 – 31) = 120 × 4.184 × (31 – 24.5)

C × 4940 = 3263.52

Divide both side by 4940

C = 3263.52 / 4940

C = 0.66 J/gºC

Learn more about heat transfer:

brainly.com/question/6363778

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6 0

2 years ago

Please help I will reward brainly

cupoosta [38]

The answer is glycolsis, I'm pretty sure.

4 0

3 years ago

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The reaction 2k(s) + br2(l) → 2kbr(s) is a(n) ______________ reaction.

Zinaida [17]

An oxidation reaction

5 0

3 years ago

Read 2 more answers

Guys help DONT SEND ME THE LINKS PLS

andrey2020 [161]

Answer:

D bohr

Explanation:

bohr model is the diagram in the picture above

6 0

3 years ago

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If a solution containing 45.101 g of mercury(II) acetate is allowed to react completely with a solution containing 12.026 g of s

AnnyKZ [126]

Answer:

14.533 grams of solid precipitate of mercury(II) dichromate will form.

Explanation:

$Hg(CH_3COO)_2(aq)+Na_2Cr_2O_7(aq)\rightarrow HgCr_2O_7(s)+2CH_3COONa(aq)$

Moles of mercury(II) acetate = $\frac{45.101 g}{318.70 g/mol}=0.14152 mol$

Moles of sodium dichromate = $\frac{12.026 g}{261.97 g/mol}=0.045906 mol$

According to reaction , 1 mole of sodium dichromate reacts with 1 mole of mercury(II) acetate , then 0.045906 moles of sodium dichromate will recat with :

$\frac{1}{1}\times 0.045906 mol=0.045906 mol$ of mercury(II) acetate

This means that mercury(II) acetate is present in an excess amount and sodium dichromate is present in limiting amount.So, amount of precipitate will depend upon moles of sodium dichromate.

According to reaction , 1 mole of sodium dichromate gives 1 mole of mercury(II) dichromate , then 0.045906 moles of sodium dichromate will give :

$\frac{1}{1}\times 0.045906 mol=0.045906 mol$ of mercury(II) dichromate

Mass of 0.045906 moles of mercury(II) dichromate:

0.045906 mol × 316.59 g/mol = 14.533 g

14.533 grams of solid precipitate of mercury(II) dichromate will form.

3 0

3 years ago