What is formed when sediment is blown against an obstacle and settles behind it

When solving an equation using Gay-Lussac's law, which of the following steps do not apply? A. List your knowns and unknowns. B.

suter [353]

Answer:

C. Plug the unknowns into the ideal gas law formula.

Explanation:

Gay-Lussac's law states that:

"For a constant mass of an ideal gas kept at constant volume, the pressure of the gas is directly proportional to its absolute temperature"

Mathematically, it can be written as:

$\frac{p_1}{T_1}=\frac{p_2}{T_2}$

where

p1 is the initial pressure

T1 is the initial temperature (in Kelvin)

p2 is the final pressure

T2 is the final temperature (in Kelvin)

Therefore, in order to solve for one of the 4 variables, the following steps must be adopted:

A. List your knowns and unknowns.

B. Convert temperature to kelvin.

D. Solve for the unknown.

While the following step is not needed:

C. Plug the unknowns into the ideal gas law formula.

Because we do not need to use the ideal gas law formula.

8 0

3 years ago

4Fe + 30₂ ⇒ Fe₂0₃

DaniilM [7]

Answer:

A

The nuber of each one should be same

5 0

1 year ago

You have a 2.0 mL sample of acetic acid (molar mass 60.05 g/mol) of unknown concentration. You titrate it to its endpoint with 2

Katyanochek1 [597]

<u>Answer:</u> The mass of acetic acid used is 0.12 grams

<u>Explanation:</u>

To calculate the concentration of acid, we use the equation given by neutralization reaction:

$n_1M_1V_1=n_2M_2V_2$

where,

$n_1,M_1\text{ and }V_1$ are the n-factor, molarity and volume of acid which is $CH_3COOH$

$n_2,M_2\text{ and }V_2$ are the n-factor, molarity and volume of base which is NaOH.

We are given:

$n_1=1\\M_1=?M\\V_1=2.0mL\\n_2=1\\M_2=0.1M\\V_2=20.0mL$

Putting values in above equation, we get:

$1\times M_1\times 2.0=1\times 0.1\times 20.0\\\\M_1=\frac{1\times 0.1\times 20.0}{1\times 2.0}=1M$

To calculate the mass of solute, we use the equation used to calculate the molarity of solution:

$\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}$

Given mass of acetic acid = ? g

Molar mass of acetic acid = 60.05 g/mol

Molarity of solution = 1 M

Volume of the solution = 2.0 mL

Putting values in above equation, we get:

$1mol/L=\frac{\text{Mass of acetic acid}\times 1000}{60.05g/mol\times 2.0}\\\\\text{Mass of acetic acid}=\frac{1\times 60.05\times 2}{1000}=0.12g$

Hence, the mass of acetic acid used is 0.12 grams

5 0

3 years ago

In the reaction between CH3CH2CH2CH2Cl and CH3ONa, the organic product is

Reptile [31]

The product of the reaction as it has been shown above is butoxymethane.

<h3>What is a chemical reaction?</h3>

A chemical reaction is an interaction that takes place between two or more chemical substances to yield a product (s). We should note that the reactants are written at the left hand side of the reaction equation while the products are written at the right hand side of the reaction equation. This is how we show reaction on paper.

Having said this, the reaction that have been shown in the question would occur by an SN2 synchronous mechanism to yield butoxy methane product.

Learn more about reaction:brainly.com/question/14080839

#SPJ1

6 0

11 months ago

Can someone please help me with an ap chem lab ill give you lots of points please!!!!!!

Novosadov [1.4K]

Answer:

Kinetic Rate Laws. The rate of the crystal violet/NaOH reaction is given by the following generalized rate law. Rate = k [OHG] [CV]. (1) x y. 25. 30.

The reaction was carried out by varying the concentrations of [CV] within the range 1.00 × 10-5 M-7.00 × 10-5 M at 298 K and fixed [NaOH]o=1.67 × 10-3 M and μ=0.085 M (KNO3). The reaction is dependent on the [CV] as observed rate constant (kobs) increases with increase in [CV] as shown in Table 1.

Explanation:

to calculate the room temperature rate constant for the reaction. BACKGROUND. Reaction Chemistry. Chemical kinetics is the study of reaction rates.

6 0

3 years ago