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VashaNatasha [74]
3 years ago
5

Look at the graph below. Which elements together make up seven percent of the Earth’s crust? calcium and iron calcium and sodium

potassium and magnesium potassium and sodium
Physics
1 answer:
yaroslaw [1]3 years ago
4 0
The graph is missing, however we can answer anyway.

In fact, this is the approximate percentage of the elements listed in the questions in the Earth's crust (data taken from wikipedia):
Iron 5.0 %
Calcium 3.6 %
Sodium 2.8 %
Potassium 2.6 %
Magnesium 1.5 %

of all of these, we see that the combination of two elements that makes up the closest number to 7% is calcium and sodium (3.6% + 2.8%=6.4%), therefore the correct answer is
Calcium and sodium.
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A

most common source of phosphates in the soil is the weathering of the mineral apatite.

Explanation:

Apatite is a group of phosphate minerals like hydroxylapatite, fluorapatite, and chlorapatite. When apatite rocks weather, they release the phosphate minerals mainly in the form of PO₄ ³⁻ . These minerals become dissolved in water (hydrosphere), where they are readily available to plants and other organisms in the biosphere. The phosphates are taken up and used in biosynthesis. When these organisms die and become buried with sediments, the phosphate gets back to the lithosphere as sedimentary rock.

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5 0
3 years ago
Given the equation E = P/N , solve for P
Mars2501 [29]

Answer:

E=P/N

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6 0
3 years ago
What is the mass of 3 m3 of a substance having density 1200 kg/m3​
adell [148]

Answer:

3600 kg

Explanation:

From the question,

Density = Mass/Volume

D = M/V.............................. Equation 1

Where D = Density of the substance, M = mass of the substance, V = Volume of the subtance.

Make M the subject of the equation

M = D×V ............................ Equation 2

Given: D = 1200 kg/m³, V = 3 m³.

Substitute these values into equation 2

M = 1200×3

M = 3600 kg.

Hence the mass of the substance is 3600 kg

4 0
3 years ago
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This is a conservation of momentum problem! Here's how to do it:

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3 years ago
At ground level g is 9.8m/s^2. Suppose the earth started to increase its angular velocity. How long would a day be when people o
velikii [3]
Let s = rate of rotation 
<span>Let r = radius of earth = 6,400km </span>
<span>Then solving (s^2) r = g will give the desired rate, from which length of day is inferred. </span>
<span>People would not be thrown off. They would simply move eastward in a straight line while the curved surface of earth fell away from beneath them.</span>
5 0
3 years ago
Read 2 more answers
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