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kupik [55]
3 years ago
15

Aluminum chloride is added to cesium does a single replacement reaction occur, and if so what is the correct chemical equation f

or this reaction
A. AlCL3 + 3Cs > No REaction
B. AlCl2 + 2Cs > 2CsCl + Al
C.AlCl3+ 3Cs > 3CsCl + Al
D. 2AlCl3 + 6Cs > 2AlCs3 + 3Cl2
Chemistry
2 answers:
krek1111 [17]3 years ago
5 0
The answer is C

I hope that helped
ss7ja [257]3 years ago
5 0

Answer: Option (C) is the correct answer.

Explanation:

When aluminium chloride reacts with cesium, then the reaction will be as follows.

        AlCl_{3} + Cs \rightarrow CsCl + Al

Number of reactant atoms are as follows.

  • Al = 1
  • Cl = 3
  • Cs = 1

Number of product atoms are as follows.

  • Al = 1
  • Cl = 1
  • Cs = 1

Thus, in order to balance the equation, multiply Cs by 3 on reactant side and multiply CsCl by 3 on the product side.

Therefore, the balanced chemical equation will be as follows.

     AlCl_{3} + 3Cs \rightarrow 3CsCl + Al    

Hence, we can conclude that out of the given options, AlCl3+ 3Cs > 3CsCl + Al is the correct chemical equation.

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how do i Calculate the grams of silver chloride produced from 18.5 ml of 4.5M magnesium chloride with 99.2 ml of 1.75 M silver n
sertanlavr [38]

Answer:

4.21 g of AgCl

3.06 g of BaCl₂ will be needed to complete the reaction

Explanation:

The first step is to determine the reaction.

Reactants: BaCl₂ and AgNO₃

The products will be the silver chloride (AgCl) and the Ba(NO₃)₂

The reaction is: BaCl₂(aq) + 2AgNO₃(aq) → 2AgCl(s) ↓ + Ba(NO₃)₂ (aq)

We determine the silver nitrate moles: 5 g . 1mol / 169.87 g = 0.0294 moles. Now, according to stoichiometry, we know that ratio is 2:2-

2 moles of nitrate can produce 2 moles of chloride, so the 0.0294 moles of silver nitrate, will produce the same amount of chloride.

We convert the moles to mass → 143.32 g / mol . 0.0294 mol = 4.21 g of AgCl.

Now, we consider the BaCl₂.

2 moles of nitrate can react to 1 mol of barium chloride

Then, 0.0294 moles of silver nitrate will react to (0.0294 . 1) /2 = 0.0147 moles. We convert the moles to mass:

0.0147 mol . 208.23 g /1mol = 3.06 g of BaCl

Explanation:

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