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kupik [55]
2 years ago
15

Aluminum chloride is added to cesium does a single replacement reaction occur, and if so what is the correct chemical equation f

or this reaction
A. AlCL3 + 3Cs > No REaction
B. AlCl2 + 2Cs > 2CsCl + Al
C.AlCl3+ 3Cs > 3CsCl + Al
D. 2AlCl3 + 6Cs > 2AlCs3 + 3Cl2
Chemistry
2 answers:
krek1111 [17]2 years ago
5 0
The answer is C

I hope that helped
ss7ja [257]2 years ago
5 0

Answer: Option (C) is the correct answer.

Explanation:

When aluminium chloride reacts with cesium, then the reaction will be as follows.

        AlCl_{3} + Cs \rightarrow CsCl + Al

Number of reactant atoms are as follows.

  • Al = 1
  • Cl = 3
  • Cs = 1

Number of product atoms are as follows.

  • Al = 1
  • Cl = 1
  • Cs = 1

Thus, in order to balance the equation, multiply Cs by 3 on reactant side and multiply CsCl by 3 on the product side.

Therefore, the balanced chemical equation will be as follows.

     AlCl_{3} + 3Cs \rightarrow 3CsCl + Al    

Hence, we can conclude that out of the given options, AlCl3+ 3Cs > 3CsCl + Al is the correct chemical equation.

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4 0
3 years ago
What is the number of moles in 15.0 g AsH3?
pentagon [3]

We are given with the mass of Arsine (AsH_{3}

The mass of arsine is 15g

there is a relation between moles, mass and molar mass of any compound which is

moles=\frac{mass}{molarmass}

The molar mass of Arsine = atomic mass of As + 3X atomic mass of H

the molar mass of Arsine = 74.92 + 3X 1 = 77.92 g/mol

Let us calculate the moles as

moles=\frac{15}{77.92}=0.192mol


7 0
2 years ago
Will give brainliest!!!!
Alekssandra [29.7K]

Answer:

Its B :)

Hope this helps

7 0
3 years ago
Having been heated to 800 K , at some point the tank starts to leak. By the time the leak is repaired, the tank contains only ha
Liula [17]

Answer: The temperature of the gas reduced to 400K.

Explanation:

Stated that ; The pressure remains the same, that is initial and final pressure equals 1atm.

Applying Charles Law

V1/T1 = V2/T2

Initial volume V1 = 1

Final volume V2 = 1/2 (halved)

Initial temperature T1 =800K

Final temperature T2 = ?

(1/800) = (1/2)/T2

T2 = 800/2

T= 400K

Therefore, when the volume is halved, the temperature reduced also to half ( 400K)

3 0
3 years ago
I need help on this question
Deffense [45]
B. I’m sorry if I’m wrong ! Wasn’t sure about this question .
5 0
2 years ago
Read 2 more answers
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