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kupik [55]
3 years ago
15

Aluminum chloride is added to cesium does a single replacement reaction occur, and if so what is the correct chemical equation f

or this reaction
A. AlCL3 + 3Cs > No REaction
B. AlCl2 + 2Cs > 2CsCl + Al
C.AlCl3+ 3Cs > 3CsCl + Al
D. 2AlCl3 + 6Cs > 2AlCs3 + 3Cl2
Chemistry
2 answers:
krek1111 [17]3 years ago
5 0
The answer is C

I hope that helped
ss7ja [257]3 years ago
5 0

Answer: Option (C) is the correct answer.

Explanation:

When aluminium chloride reacts with cesium, then the reaction will be as follows.

        AlCl_{3} + Cs \rightarrow CsCl + Al

Number of reactant atoms are as follows.

  • Al = 1
  • Cl = 3
  • Cs = 1

Number of product atoms are as follows.

  • Al = 1
  • Cl = 1
  • Cs = 1

Thus, in order to balance the equation, multiply Cs by 3 on reactant side and multiply CsCl by 3 on the product side.

Therefore, the balanced chemical equation will be as follows.

     AlCl_{3} + 3Cs \rightarrow 3CsCl + Al    

Hence, we can conclude that out of the given options, AlCl3+ 3Cs > 3CsCl + Al is the correct chemical equation.

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What would be the mass in grams of 8.94 x 10 22 formula units of copper(II) fluoride, CuF 2
Nadya [2.5K]

The mass in grams of 8.94×10²² formula units of CuF₂ is 15.07 g

<h3>Avogadro's hypothesis </h3>

6.02×10²³ formula units = 1 mole of CuF₂

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1 mole of CuF₂ = 101.5 g

Thus,

6.02×10²³ formula units = 101.5 g of CuF₂

<h3>How to determine the mass of 8.94×10²² formula units of CuF₂</h3>

6.02×10²³ formula units = 101.5 g of CuF₂

Therefore,

8.94×10²² formula units = (8.94×10²² × 101.5 ) / 6.02×10²³

8.94×10²² formula units = 15.07 g of CuF₂

Thus, 8.94×10²² formula units are present in 15.07 g of CuF₂

Learn more about Avogadro's number:

brainly.com/question/26141731

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