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Brrunno [24]
3 years ago
14

Explain how you can determine from the periodic table exactly how many neutrons are in an atom?

Chemistry
1 answer:
Ronch [10]3 years ago
5 0

Answer:

The numbers in the corner

Explanation:

Using the numbers in the corner, we know that they will tell us the number of neutrons, thus forth answering your question.

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1. Complete the balanced dissociation equation for the compound below. If the compound does not dissociate, write NR after the r
puteri [66]

Answer:

1. (NH₄)₂S(s) -----> NH₄+(aq) + S²-(aq)

2. Al³+ (aq) + PO₄³+ (aq) ----> AlPO₄ (s)

Explanation:

The dissociation of ammonium sulphide, (NH₄)₂S when dissolved in water is given in the equation below:

(NH₄)₂S(s) -----> NH₄+(aq) + S²-(aq)

However very little S²- ions are present in solution due to the very basic nature of the S²- ion (Kb = 1 x 105).

The ammonium ion being a better proton donor than water, donates a proton to sulphide ion to form hydrosulphide ion which exists in equilibrium with aqueous ammonia.

S²- (aq) + NH₄+ (aq) ⇌ SH- (aq) + NH₃ (aq)

Aqueous solutions of ammonium sulfide are smelly due to the release of hydrogen sulfide and ammonia, hence, their use in making stink bombs.

2. The reaction between aluminium nitrate and sodium phosphatein aqueous solution is a double decomposition reaction whish results in the precipitation of insoluble aluminium phosphate. The equation of the reaction is given below :

Al(NO₃)₃ (aq) + Na₃PO₄ (aq) ----> AlPO₄ (s) + 3 NaNO₃ (aq)

The net ionic equation is given below:

Al³+ (aq) + PO₄³+ (aq) ----> AlPO₄ (s)

7 0
3 years ago
Calculate the mass of aluminum in 500 g of Al(C2H3O2)3
Luden [163]
Answer: 66.2 g

Explanation:

1) The ratio of Al in the molecule is  1 mol to 1 mol .

2) The mass of 1 mol of molecules of Al (CH2H3O2)3 is the molar mass of the compound.

3) You calculate the molar mass of the compound using the atomic masses of each atom, in this way:

Al: 27 g/mol
C: 2 * 3 * 12 g/mol = 72 g/mol
H: 3 * 3 * 1 g/mol = 9 g/mol
O: 2 * 3 * 16 g/mol = 96 g/mol

Molar mass = 27 g/mol + 72 g/mol + 9 g/mol + 96 g/mol = 204 g/mol

4) Set a proportion:

    27 g/mol                x
-------------------- =  ----------
   204 g/mol            500 g

5) Solve for x:

x = 500 g * 27 g/mol / 204 g/mol = 66.2 g
5 0
4 years ago
1. An oxide of chromium is found to have the following % composition: 68.4% Cr
abruzzese [7]

Answer:

Empirical formula is Cr₂O₃.

Explanation:

Given data:

Percentage of Cr = 68.4%

Percentage of O = 31.6%

Empirical formula = ?

Solution:

Number of gram atoms of Cr = 68.4 / 52 = 1.3 2

Number of gram atoms of O = 31.6 / 16 = 1.98

Atomic ratio:

                            Cr               :         O

                           1.32/1.32     :       1.98/1.32

                               1              :        1.5

Cr : O = 1 :  1.5

Cr : O = 2(1 : 1.5)

Empirical formula is Cr₂O₃.

6 0
3 years ago
Which of these observations helped Rutherford determine that atoms have tiny, dense, positively charged nuclei?
gladu [14]
The third reason helped Rutherford to discover the nucleus.
5 0
3 years ago
A mixture is made by combining 1.62 lb of salt and 5.20 lb of water.
Galina-37 [17]

Answer:

oof idk I would suggest looking at an example and try going off that

7 0
3 years ago
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