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german
3 years ago
7

Which set up would correctly complete the work for determining how many moles of NaOH will be produced if 10.5 grams of water (H

2O) is used?

Chemistry
1 answer:
Angelina_Jolie [31]3 years ago
5 0

Answer:

B: 2 mol NaOH/2 mol H2O

Explanation:

The reaction equation is;

H2SO4 + 2NaOH = Na2SO4 + 2H20

Now, to know how many moles of NaOH will be produced for 10.5 grams of water (H2O) used, and since the molar mass of H2O is 18.02 g/mol and number of moles attached to H2O and NaOH in the reaction are both 2 we will have;

10.5g H2O × 1 mol H2O/18.02 g H2O × 2 mol NaOH/2 mol H2O

Thus correct answer is option B

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What is the molarity of a solution that contains 122g of MgSO4 n 3.5L of solution?​
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Answer:

0.29mol/L or 0.29moldm⁻³

Explanation:

Given parameters:

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Molarity = number of moles/ Volume

>>>>To calculate the Molarity of MgSO₄ we find the number of moles using the mass of MgSO₄ given.

Number of moles = mass/ molar mass

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Molarity = number of moles/ Volume

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= 0.29mol/L

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