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german
3 years ago
7

Which set up would correctly complete the work for determining how many moles of NaOH will be produced if 10.5 grams of water (H

2O) is used?

Chemistry
1 answer:
Angelina_Jolie [31]3 years ago
5 0

Answer:

B: 2 mol NaOH/2 mol H2O

Explanation:

The reaction equation is;

H2SO4 + 2NaOH = Na2SO4 + 2H20

Now, to know how many moles of NaOH will be produced for 10.5 grams of water (H2O) used, and since the molar mass of H2O is 18.02 g/mol and number of moles attached to H2O and NaOH in the reaction are both 2 we will have;

10.5g H2O × 1 mol H2O/18.02 g H2O × 2 mol NaOH/2 mol H2O

Thus correct answer is option B

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Please help thaank youu
krek1111 [17]
First, let's start off by finding the mass of this whole hydrate.
(Note: the unit of measurement for mass will be amu)

Let's find the molecular mass of each element.
Co=58.933
Cl=35.45
H=1.008
O=15.999

Now, let's find the mass of each compound.

CoCl_2=58.933+2(35.45)=129.833
H_2O=2(1.008)+15.999=18.015

We have 6 molecules of H2O, so multiply 18.015 by 6 then add that with the weight of CoCl2.

6(18.015)=108.09
129.833+108.09=237.923

Now divide 108.09 (mass of all the H2O in the hydrate) by 237.923 (total mass of hydrate).

\dfrac{108.09}{237.923}

\approx0.45431

Turn that into a percentage and you get 45.431%.
Hope this helps! :)
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Answer:

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