The answer is A vaporization
Answer:
A.) 27000 kgm/s
18000 kgm/s
B.) Va = 22 m/s
C.) 19800 kgm/s
25200 kgm/s
Explanation: Given that the velocity of A and B are 30 m/s and 20 m/s. And of the same mass M = 9 × 10^5g
M = 9×10^5/1000 = 900 kg
A.) Initial momentum of A
Mu = 900 × 30 = 27000 kgm/s
Initial momentum of B
Mu = 900 × 20 = 18000 kgm/s
B.) if they have an accident and then the velocity of the B is 28 m/s, find out velocity of A.
Momentum before impact = momentum after impact
Given that Vb = 28 m/s
27000 + 18000 = 900Va + 900 × 28
45000 = 900Va + 25200
900Va = 45000 - 25200
900Va = 19800
Va = 19800/900
Va = 22 m/s
C.) Momentum of A after impact
MV = 900 × 22 = 19800 kgm/s
Momentum of B after impact
MV = 900 × 28 = 25200 kgm/s
Disposing of hazardous waste in a labeled container
Answer:
Simple answer: Yes
Explanation:
Even if you touch an item with a stick you re still doing work to it, most of the time something sitting on a table not being disturbed is having work done to it. Everything has the force of gravity working on it to essentially keep the items from floating away so workis being done to it.
Work done can be something so small (e.g) a pencil sitting on a table) or as big as an earthquake or kicking a ball through a window and smashing the glass.
Answer:
A. 0.0096 W/m²
B. 11.603 dB
C. 827.37 m/s
Explanation:
Parameters given:
Frequency, f = 274Hz
Pressure, P = 101.3 kPa
Temperature, T = 25°C = 298K
Power = 30 mW
Radial distance, = 500 mm = 0.5 m
A. Intensity = Power/Area
Intensity = Power/(4*pi*r²)
= (30 * 10^(-3))/(4 * 3.142 * 0.5²)
= 0.0096 W/m²
B. Pressure(rms) = √(I*ρ*c)
I = Intensity
ρ = density
c = speed of sound
ρ = P/RT
R = gas constant
=> ρ = (101.3 * 10^3) / (298 * 8.314)
ρ = 40.89 kg/m³
=> Pressure(rms) = √(0.0096 * 40.89 * 343)
= √(134.64)
= 11.603 dB = 11.603 * 10^(-6) Pa
C. Acoustic Particle velocity = Intensity/ Acoustic Pressure
Acoustic Particle velocity = 0.0096 / (11.603 * 10^(-6)
Acoustic Particle velocity = 827.37 m/s
